Question

The density of Maplewood is 39 pounds per cubic foot. If a cylindrical maple tree stump is 3 feet high and has a radius of 1.5 feet, what is the weight of the stump to the nearest pound? Use 3.14 for pi, and enter the number only.

Answer 1

Answer: 827 pounds.

Step-by-step explanation:

The formula for calculate density is:

$d=\frac{m}{V}$

Where "m" is the mass and "V" is the volume.

The formula for calculate the volume of a cylinder is:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height.

Calculate the volume of the cylindrical maple tree stump, which is 3 feet high and has a radius of 1.5 feet:

$V=(3.14)(1.5ft)^2(3ft)=21.195ft^3$

Substitute the volume into and the density 39 pounds per cubic foot, into the formula $d=\frac{m}{V}$ and solve for "m". Then, the weight of the stump to the nearest pound is:

$39\frac{lb}{ft^3}=\frac{m}{21.195ft^3}\\\\m=(39\frac{lb}{ft^3})(21.195ft^3)\\\\m=827lb$