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mylen [45]
3 years ago
14

A length of thread measured 2/7 m long. Mr. Keller used 3/5 of it. How much thread did he have left?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0

Answer:

-11/35

Step-by-step explanation:

2/7-3/5

10/35-21/35

-11/35

Black_prince [1.1K]3 years ago
4 0

Answer:

-11 / 35 is left

Step-by-step explanation:

Basically you just subtract the used length from the total length of the thread.

2/7 - 3/5

Make the denominators same before beginning!

Times 5 by both 2 and 7(top and bottom)

Times 7 by both 3 and 5(top and bottom)

(10-21)/35

= -11 / 35

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

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The probability of Erin not having a heart attack according to her family history would be 30%.

The probability of the test predicting correctly is 67%.

Therefore, the probability of the test correctly predicting that Erin will not have a heart attack would be (0.30)(0.67) = 0.201 or 20.1%.
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3 years ago
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The following are the temperatures in °C for the first 10 days in January:
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Answer:

15.4 is the range.

Step-by-step explanation:

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2 years ago
a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

3 0
3 years ago
Need this for my math test?
docker41 [41]

Answer:

519.6

Step-by-step explanation:

A hexagon has a total of 720 for it's interior angles so each angle is 120 and in the triangle, each of them is 60, making it an equilateral triangle. You can use 30 60 90 triangles to find the height which is 5√3.

(5√3)*10=50√3

The area of the triangle times 6 is 300√3 which is approximately 519.6

7 0
3 years ago
Write the equation of the line perpendicular to 2x+3y=9 that passes through (-2,5). Write your answer in slope-intercept form. S
amid [387]

Answer:

y = (3/2)x + 8

Step-by-step explanation:

Hi

First let's find the slope of the given line by converting to slope-intercept form:-

2x + 3y = 9

3y = -2x + 9

y = (-2/3)x + 3

From this we see that the slope is -2/3.

The slope of a line perpendicular to this one will be - 1 /  (-2/3)

= 3/2.    ( because for a line and its perpendicular, the slopes' product = -1).

Using the point-slope form  to find the equation of this line

y - y1 = m(x - x1).  Here m = slope and (x1, y1) is a point on the line.

Plugging in the given values ,  m = 3/2 , x1 = -2 and y1 = 5:-

y - 5 = 3/2 (x - -2)

y - 5 = 3/2x + 3

y = (3/2)x + 8   which is the equation in slope-intercept form.

8 0
3 years ago
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