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mylen [45]
3 years ago
14

A length of thread measured 2/7 m long. Mr. Keller used 3/5 of it. How much thread did he have left?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0

Answer:

-11/35

Step-by-step explanation:

2/7-3/5

10/35-21/35

-11/35

Black_prince [1.1K]3 years ago
4 0

Answer:

-11 / 35 is left

Step-by-step explanation:

Basically you just subtract the used length from the total length of the thread.

2/7 - 3/5

Make the denominators same before beginning!

Times 5 by both 2 and 7(top and bottom)

Times 7 by both 3 and 5(top and bottom)

(10-21)/35

= -11 / 35

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

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3 years ago
Please help me. It's urgent​
siniylev [52]

Answer:

a) 7/5

Step-by-step explanation:

y-\frac{y-1}{2}=1-\frac{y-2}{3}  \\Through\ the\ butterfly\ method\ of\ resolving\ denominators\ ,\\\frac{2y-(y-1)}{2} = \frac{3-(y-2)}{3} \\\frac{2y-y+1}{2} = \frac{3-y+2}{3} \\\frac{y+1}{2} =\frac{5-y}{3} \\3(y+1)=2(5-y)\\3y+3=10-2y\\3y+2y=10-3\\5y=7\\y=\frac{7}{5}

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