Answer:
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Step-by-step explanation:
The local minimum of function is an argument x for which the first derivative of function g(x) is equal to zero, so:
g'(x)=0
g'(x)=(x^4-5x^2+4)'=4x^3-10x=0
x(4x^2-10)=0
x=0 or 4x^2-10=0
4x^2-10=0 /4
x^2-10/4=0
x^2-5/2=0
[x-sqrt(5/2)][x+sqrt(5/2)]=0
Now we have to check wchich argument gives the minimum value from x=0, x=sqrt(5/2) and x=-sqrt(5/2).
g(0)=4
g(sqrt(5/2))=25/4-5*5/2+4=4-25/4=-9/4
g(-sqrt(5/2))=-9/4
The answer is sqrt(5/2) and -sqrt(5/2).
I’m pretty positive it is just 5.70 you just take out the 4.
Step-by-step explanation:
the first question
x²+x+5
when x is -4
(-4)²+(-4)+5
16-4+5
12+5
17
hope this was helpful
The word "times" means you have to multiply.
2 1/5 times 1 3/4 is 3 17/20.
The phrase "how many more" means you have to subtract.
3 17/20 minus 2 1/5 is 1 13/20.
Carson walked her dog 1 13/20 more miles than Claire did.
Sorry for the lazy explanations Imao
