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Anestetic [448]
3 years ago
6

madison makes dinner using 1 box of farfalle noodles and 1 jar of marsala sauce. if farfalle is sold in packages of 4 boxes and

marsala is sold in 3 jars, what is the least number that madison can make without any supplies left over?
Mathematics
2 answers:
soldi70 [24.7K]3 years ago
8 0

Answer:

The answer is 12 boxes (3 packages) and 12 jars (4 packages).

Step-by-step explanation:

You have to find the least common multiple of 3 and 4.

3, 6, 9, 12, 15

4, 8, 12, 16, 20

The least common multiple is 12, so that is the answer.

Hope this helps!

ICE Princess25 [194]3 years ago
3 0

Answer:

<u>12 boxes (3 packages) and 12 jars (4 packages).</u>

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Which graph represents the solution set of the system of inequalities? {x+y&lt;12 y≥x−4
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Answer: The graph in the bottom right-hand corner

(see figure 4 in the attached images below)

===========================================

Explanation:

Let's start off by graphing x+y < 1. The boundary equation is x+y = 1 since we simply change the inequality sign to an equal sign. Solve for y to get x+y = 1 turning into y = -x+1. This line goes through (0,1) and (1,0). The boundary line is a dashed line due to the fact that there is no "or equal to" in the original inequality sign. So x+y < 1 turns into y < -x+1 and we shade below the dashed line. The "less than" means "shade below" when y is fully isolated like this. See figure 1 in the attached images below.

Let's graph 2y >= x-4. Start off by dividing everything by 2 to get y >= (1/2)x-2. The boundary line is y = (1/2)x-2 which goes through the two points (0,-2) and (4,0). The boundary line is solid. We shade above the boundary line. Check out figure 2 in the attached images below.

After we graph each individual inequality, we then combine the two regions on one graph. See figure 3 below. The red and blue shaded areas in figure 3 overlap to get the purple shaded area you see in figure 4, which is the final answer. Any point in this purple region will satisfy both inequalities at the same time. The solution point cannot be on the dashed line but it can be on the solid line as long as the solid line is bordering the shaded purple region. Figure 4 matches up perfectly with the bottom right corner in your answer choices.

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Step-by-step explanation:

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Also, see the attached figure that represents the given function.

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