Answer:
Commuttative Property for Addition
Step-by-step explanation:
There is the answer above
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
1st digit cannot be 0 so there are 9 choices {1,2,3,4,5,6,7,8,9}. The middle 4 digits have 10 choices (can have 0). The last digit must be EVEN or 0 to make the entire 6 digit number even, {0,2,4,6,8} = 5 choices
9×10×10×10×10×5 = 450,000
The answer is 2,16. Hope that helps.
3x - 15 < 4x - 2
3x - 4x < -2 + 15
-x < 13
x > -13