Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
True because it wouldn’t have made since if it was false
200
Hope it’s right
Best luck with your studying
Answer: 6.5 and 6 is the 9th term
Step-by-step explanation:
Answer:
HCF=3
Step-by-step explanation:
Factors of 15t= 3*5*t
Factors of 6s= 2*3*s
HCF= Common factors
common factor = 3
HCF=3