Hello!
Answer:
1. first u want to distribute the 3
3(n+4)+2
3n+12+2
Then add 12 and 2
3n+14
2. again, distribute
5(w+2)+3w-4
5w+10+3w-4
subtract
5w+10-4+3w-4-4
combine like terms
5w+3w+6+3w+3w
8w+6
3. distribute
3(w-2y)+w+4
3w-6y+w+4
Combine like terms
4w-6y+4
these are the first 3. if this is not what you wanted pls reach out! Hop this helps! :)
40,561÷ 47= 863
Hoped this helped.
~Bob Ross®
Total=shirtcost+tax
shirtcost=100%
8.5%+100%=108.5%=1.085
1.085 times 25.99=28.19915
round
total cost is
$28.20
The constant of proportionality is 1/3
and three more values are
x 1 2 3 4 5
y 3 6 9 12 15
<h3>Variation</h3>
From the question, we are to determine the constant of proportionality
The given equation is
k = x ÷ y
From the given information,
When x = 1, y = 3
∴ k = 1 ÷ 3
k = 1/3
Thus, the constant of proportionality is 1/3
Now, we will determine the values of y for the values x = 3, x = 4, and x = 5
Since
k = x ÷ y
Then,
y = x ÷ k
When x = 3
y = 3 ÷ 1/3
y = 3 × 3
y = 9
When x = 4
y = 4 ÷ 1/3
y = 4 × 3
y = 12
When x = 5
y = 5 ÷ 1/3
y = 5 × 3
y = 15
Hence, the constant of proportionality is 1/3
and three more values are
x 1 2 3 4 5
y 3 6 9 12 15
Learn more on Variation here: brainly.com/question/19641181
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Answer:
See below (I hope this helps!)
Step-by-step explanation:
Because odd numbers are always 1 greater than even numbers, we can call the two odd numbers x + 1 and y + 1 where x and y are even integers. Multiplying the two gives us:
(x + 1) * (y + 1)
= x * y + x * 1 + 1 * y + 1 * 1
= xy + x + y + 1
We know that x * y will be even because x and y are also even and the sum of two even numbers will be even, and we also know that x and y are even and that 1 is odd. Since the sum of even and odd numbers is always odd, the product of any two numbers is always odd.
*NOTE: I put a limitation on x and y in my proof (the limitation was that x and y must be EVEN integers) but you don't have to do that, you could make the odd integers 2x + 1 and 2y + 1 where x and y could be any integer from the set Z like mirai123 did. I simply gave this proof because it was the first thing that came to mind. While mirai123's proof and mine are different, they are still both correct.
