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3 years ago

What value of x would make KM ∥ JN?

Mathematics

1 answer:

stepan [7]3 years ago

4 0

Answer:

x = 10

Step-by-step explanation:

By the converse of the side-splitter theorem, if $\dfrac{JK}{KL}= \dfrac{NM}{ML}$ , then KM ∥ JN.

Substitute the expressions into the proportion:

$\dfrac{x-5}{x}= \dfrac{x-3}{x+4}$

Cross-multiply:

(x – 5)(x+4) = x(x – 3).

Distribute:

$x(x) + x(4) - 5(x) - 5(4) = x(x) + x(-3).$

Multiply and simplify:

$x^2 +4x- 5x - 20 = x^2-3x\\-x-20=-3x\\$Collect like terms$\\-x+3x=20\\2x=20\\$Divide both sides by 2\\x=10$

Solve for x: x = 10

Therefore, the value of x that would make KM parallel to JN is 10.

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A bowl contains 28 black, 21 red, 23 blue, and 10 green balls

Licemer1 [7]

Answer:

P (blue) = 23 / 82

Step-by-step explanation:

There are 23 blue out of 82 (28 + 21 + 23 + 10 = 82) balls

or,

23 / 82

So, the probability of a blue ball being chosen is 23/82

(or a 28% chance [rounded])

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2 years ago

Jonathan and his sister Jennifer have a combined age of 48. If Jonathan is twice as old as his sister, how old is Jennifer

Pani-rosa [81]

The age of Jennifer is 16.

<h3>What is Jennifer's age?</h3>

Let Jennifer's age be represented with x

Jonathan's age would be 2x

The sum of their ages would be 48

2x + x = 48

3x = 48

x = 48 /3 = 16

To learn more about addition, please check: brainly.com/question/19628082

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2 years ago

Plssss helpppp thankssssss

Vlad [161]

Answer:

Step-by-step explanation:

6/2 = 3

because the triangle is halved

use pythagorus 3²+4²=25

√25 = 5

so x=5

4 0

2 years ago

Write an equation of the line that passes through (−1,3) and is parallel to the line y=2x+2

Komok [63]

Start off by writing the equation y = mx - b. Then plug in what you do know

3 = 2(-1) - b (m is the slope and parallel lines have the same slope). Then solve

3 = -2 - b

5 = b

So y = 2x + 5

6 0

3 years ago

Help! Hurry! NO SPAM!!!! I will mark brainliest if you get it correct, and show your work. Identify the equation for the circle

kotegsom [21]

First we compute the distance between the center and the given point which is exactly the radius

r =

$\sqrt{(x2 - x1) + (y2 - y1)} = \sqrt{9 - 3 + 11 - 7} = \sqrt{10}$

Now that we know the center and the radius, we can write the equation of a circle with given radius and center:

${(x - h)}^{2} + {(y - k)}^{2} = {r}^{2}$

where (h,k) represent the coordinates of the center (3,7).

We substitute and obtain

${(x - 3)}^{2} + {(y - 7)}^{2} = { \sqrt{10} }^{2} \\ {(x - 3)}^{2} + {(y - 7)}^{2} = 10 \\ {x}^{2} - 6x + 9 + {y}^{2} - 14y + 49 = 10 \\ {x}^{2} + {y}^{2} - 6x - 14y + 48 = 0$

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3 years ago