Answer:
B is True
A, C. D are false
Step-by-step explanation:
Given :
Sample size, n = 120
Mean diameter, m = 10
Standard deviation, s = 0.24
Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96
The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.
The population here is N = 10000
To obtain
Confidence interval (C. I) :
Mean ± margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.96 * 0.24/sqrt(120)
Confidence interval for the 10,000 ball bearing :
10 ± 1.96 * (0.24) / sqrt(120)
Hence. The confidence interval defined as :
10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.
The modifications made to the list of assets and liabilities that would result in an increase in net worth is Option D. Net worth is defined as the value of all the non-financial and financial assets owned by an individual or an institution.
All of the above (Putting $100 in savings, Paying $100 on credit cards and Getting paid $100)
