Answer:
The wedge cut from the first octant ⟹ z ≥ 0 and y ≥ 0 ⟹ 12−3y^2 ≥ 0 ⟹ 0 ≤ y ≤ 2
0 ≤ y ≤ 2 and x = 2-y ⟹ 0 ≤ x ≤ 2
V = ∫∫∫ dzdydx
dz has changed from zero to 12−3y^2
dy has changed from zero to 2-x
dx has changed from zero to 2
V = ∫∫∫ dzdydx = ∫∫ (12−3y^2) dydx = ∫ 12(2-x)-(2-x)^3 dx =
24(2)-6(2)^2+(2-2)^4/4 -(2-0)^4/4 = 20
Step-by-step explanation:
Answer:
19.5 = CD
Step-by-step explanation:
The square of the tangent = the the whole secant times the outside part of the secant.
EG²= (ED)(EC)
13² = (26)(EC)
169 = 26EC
169/26 = EC
6.5 + EC
Now ED = EC + CD
26 = 6.5 + CD
26 - 6.5 = CD
19.5 = CD
Answer: Y intercept: 5 The slope of the line is: 2
Step-by-step explanation:
Y=mx+b is y-intercept form
So you have to solve this equation for y.
This looks like:
-2x+y=5
+2x +2x
y=2x+5
Answer:
nearest number
Step-by-step explanation:
Answer:
B is correct
Step-by-step explanation:
