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lora16 [44]
3 years ago
14

What is 0.9 as a percentage

Mathematics
1 answer:
Tanya [424]3 years ago
7 0
Answer is 90% of 1.
90÷100×1=0.9
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A polynomial p has zeros when I = 0.2 = -
Rainbow [258]

Answer:

p(x) = (5x - 1) (x + 3)

Step-by-step explanation:

I apologize if I couldn't answer correctly, the question was a bit hard to understand because of the formatting.

Also I didn't see my answer in the list of answer choices but here it is:

if the polynomial has zeros at 0.2 and -3 the equation would have to be:

p(x)=(x-0.2)(x+3)

This is because plugging either of those numbers into the polynomial would cause it to equal 0.

(x-0.2) can be simplified by multiplying everything in the parenthesis by 5, getting rid of all of the decimals, making the final answer:

p(x) = (5x - 1) (x + 3)

5 0
3 years ago
INDEPENDENT:
Leni [432]

Answer: your answers are correct. I inserted an image of the answers.

3 0
3 years ago
2 tan 30°<br>II<br>1 + tan- 300​
shusha [124]

Question:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Answer:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

Step-by-step explanation:

Given

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}

Required

Simplify

In trigonometry:

tan(30^{\circ}) = \frac{1}{\sqrt{3}}

So, the expression becomes:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}

Simplify the denominator

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}

Express the fraction as:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= \frac{2}{\sqrt 3} / \frac{4}{3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{2}{\sqrt 3} * \frac{3}{4}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{1}{\sqrt 3} * \frac{3}{2}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3}

Rationalize

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{3\sqrt{3}}{2* 3}

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})} = \frac{\sqrt{3}}{2}

In trigonometry:

sin(60^{\circ}) =  \frac{\sqrt{3}}{2}

Hence:

\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}= sin(60^{\circ})

3 0
3 years ago
Please help me with this problem 4/7+q =10
Agata [3.3K]
9= 66/7. And 66/7= 9 3/7
8 0
3 years ago
Read 2 more answers
Suppose the heights of the members of a population follow a normal distribution. If the mean height of the population is 68 inch
Irina18 [472]

The empirical rule states that at 95% the measurements would be within 2 standard deviations of the mean.


You are given a mean of 68 inches and a standard deviation of 4.

2 times the standard deviation = 2 x 4 = 8

So 95% of the heights would be between 68-8 = 60 inches and 68+8 = 76 inches.

4 0
3 years ago
Read 2 more answers
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