All categories

3 years ago

Line segment BD bisects < CBE, line segment BD bisects

Mathematics

1 answer:

GarryVolchara [31]3 years ago

8 0

Jajwjwhwjshjwjwhwhwhw

You might be interested in

Find area of a parallelogram with a height of 8 inches and a base of 14 inches

12345 [234]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{112 \: {inches} \: ^{2} }}}}}$

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

Finding the area of a parallelogram

$\boxed{ \sf{area \: of \: parallelogram \: = \: base \: \times \: height}}$

⇒ $\sf{area \: of \: parallelogram \: = \: 14 \: \times 8}$

⇒ $\sf{area \: of \: parallelogram = 112 \: {inches}^{2} }$

Hope I helped!

Best regards! :D

4 0

3 years ago

The depth of water in a swimming pool decreases by 1/8 inch per day due to evaporation. No water is added to the pool for a 2-we

Blababa [14]

Answer:

uwiejejdkdm

Step-by-step explanation:

द्ज्द्क्क्स्क्द्क्क्द्क्द्क्द्क्फोक्स्म्स्वेज्र

3 0

3 years ago

20 = 4x+ 6 is equivalent to the equation 24 = 4x + 10

Kruka [31]

Answer:

Addition Property

Step-by-step explanation:

Added 4 on both sides to equate the solution

5 0

3 years ago

Read 2 more answers

Does anyone have any idea how to solve this problem?

Katena32 [7]

Answer:

$1350

Step-by-step explanation:

(150 x 30) + (300 x 45) = 18000

18000 x 0.075 = 1350

7 0

3 years ago

RSTU is a rectangle with vertices at R(-3,1), S(1 ,1), T(-3,3) and U (1, 3). Describe two lines of reflection that would carry t

miss Akunina [59]

Answer:

The two lines of reflection are $x=-1$ and $y=2$

Step-by-step explanation:

I will attach a file with the graph of the rectangle and the lines of reflection.

We know that RSTU is a rectangle with vertices at $R=(-3,1)$ , $S=(1,1)$ ,

$T=(-3,3)$ and $U=(1,3)$

The first step is to draw the vertices on the plane and them the rectangle.

The rectangle is a symmetrical figure. Therefore if we want to carry the rectangle onto itself using a line of reflection this line must goes through the centroid of the rectangle.

Given that we have a rectangle whose width is $a$ and its length is $b$ its centroid will be place at $(\frac{a}{2},\frac{b}{2})$ .

Looking at the graph and using this information we find that the two lines of reflection are $x=-1$ and $y=2$ .

6 0

3 years ago