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jeka94
3 years ago
10

Describe fully the single transformation that maps triangle a onto triangle b

Mathematics
1 answer:
Katena32 [7]3 years ago
4 0
Reflection across y=-2 followed by a translation 2 units up
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A certain 90-mile trip took 2 hours. Exactly 1/3 of the distance traveled was by rail and this part of the trip took 1/5 of the
antiseptic1488 [7]

The average rate, in miles per hour, of the rail portion of the trip is; D: 75

<h3>How to calculate the average speed?</h3>

Since exactly 1/3 of the distance travelled was by rail, then we can say that;

(1/3) * (90) = 30 miles

We are told that part of the trip took 1/5 of the travel time. Thus;

Time it takes to travel that distance is:

(1/5) * (2) = 2/5 of an hour

Average rate is;

30/(2/5) = 150/2 = 75 mph

Read more about Average speed at; brainly.com/question/4931057

#SPJ1

7 0
2 years ago
If y=-5 when x=2,find y when x=8
LenaWriter [7]
You can’t really know the y value unless you’re told that they’re both directly proportional. if so, then check out the pic

5 0
3 years ago
1. What is the solution to this equation?<br> 2 x + 10 = 28
Colt1911 [192]

Answer:

9

Step-by-step explanation:

2x=28-10

2x=18

x=18÷2

x=9

3 0
3 years ago
Read 2 more answers
Please help with this
klemol [59]

Answer:

(h+k)(2)=4+1+2-2=5

(h-k)(3)=9+1-3-2=3+1-1=9

3h2+2k3=3*5+2=17

7 0
3 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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