<em>Hi there!</em>
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<em>Distribute the Negative Sign:</em>
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<em>Combine Like Terms:</em>
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<em>Answer : </em>
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<em>Hope this helped you!</em>
The missing dimension, x, is 7.5.
if you take 45 and divide it by 6 you can get the next dimension needed to get the full number, 45. You can also find it by dividing 35 and 4. I hope this helps.
If there were only sandwiches bought, there would be 15, if there were only salads bought there would be 20. There’s probably more than one possibility, but that’s the best I can do, considering how long it’s been since I’ve done this type of problem. I’m all the way to learning determinants, so I really have to think to remember these. Sorry in advance if this doesn’t help at all, I’m not the best at this, but I can still try.
Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.
Now, Pythagoras' Theorem is defined as follows:
c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:
c^2 = a^2 + b^2
24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)
b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)
b = √(24^2 - 8^2) (Take the square root of both sides)
b = √512 (Evaluate 24^2 - 8^2)
b = 16√2 (Simplify √512)
= 22.627 (to three decimal places)
I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.
(0, 2 ), (4,5)
to draw a graph of a straight line , we only require 2 points
select any 2 values for x, substitute them into the equation for the corresponding y- coordinates
x = 0 → y = 0+2 = 2 ⇒ (0, 2)
x = 4 → y = 3+2 = 5 ⇒ (4, 5)
Plot these 2 points and draw a straight line through them for graph
