Given

Divide it by (x+1) using synthetic division, as shown below
The green line is a minus sign.
Thus,

Therefore, since the remainder is different than zero, (x+1) is not a factor of 4x^2+2x-5
Simplify by dividing the two by 14
Answer:
5x=55
Divide both sides by 5 to solve for x
5x/5=55/5
x=11
Answer:
£110
Step-by-step explanation:
We know how much time it takes for a boiler and a radiator, and we need to know how much it will cost for 1 boiler and 4 radiators. We have an initial cost of £30, and since hes doing a boiler - which we know takes an hour - we can already add £20 for a start of £50.
Now, there are 4 radiators, that take 45 minutes each. We need to use this equation:

We divide by 60 because there are 60 minutes in an hour, and he charges by hour. So:

Now, to find out how much to charge, we need to figure out how much to add to the £50. Since it's £20 an hour, and it takes 3 hours to do the 4 radiators, we need to multiply:

Now we add our totals for a grand total of...

17+3=20
740/20=37 Classes
37 classes x 3 faculty members=111