Answer:
$15
Step-by-step explanation:
Let Sam's Money =s
Let Janet's Money =j
of Sam's money equals of Janet's money.
Let n be the number of dollars held by Sam and Jane respectively
Therefore:
s=3n
j=2n
s+j=3n+2n=5n
Together, they have more than $10
5n>10
n>2
The least sum they could have is at n=3
At n=3
s+j=5n=5X3=$15
The least number of dollars they could have combined is $15.
2/7
-1 1/7 + 6/7 = -8/7 + 6/7 = 2/7
1+2=3
Just add all side
5+11+5+11=32 feet