Question

When a number is increased by 8.2%, the result is 106. What is the original number to the nearest tenth?

Answer 1

Answer:

Step-by-step explanation:

Let the original number = x

$x+\frac{8.2}{100}*x=106\\\\x+0.082x=106\\\\1.082x=106\\\\x=\frac{106}{1.082}\\\\x=\frac{106*1000}{1.082*1000}\\\\x=\frac{106000}{1082}\\\\x=97.96$

x=98.0

x=98