Answer: the tuition in 2020 is $502300
Step-by-step explanation:
The annual tuition at a specific college was $20,500 in 2000, and $45,4120 in 2018. Let us assume that the rate of increase is linear. Therefore, the fees in increasing in an arithmetic progression.
The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500
The fee in 2018 is the 19th term of the sequence. Therefore,
T19 = $45,4120
n = 19
Therefore,
454120 = 20500 + (19 - 1) d
454120 - 20500 = 19d
18d = 433620
d = 24090
Therefore, an
equation that can be used to find the tuition y for x years after 2000 is
y = 20500 + 24090(x - 1)
Therefore, at 2020,
n = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Answer:
3 and 9
Step-by-step explanation:
3 * 24 = 72
9 * 8 = 72
3 * 15 = 45
9 * 5 = 45
Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
<span>Cone Volume = (<span>π<span> • r² •<span> h) ÷ 3
Original cone = (3.14 * 6^2 * 12) / 3
</span></span></span></span>
<span><span>Original cone = 452.16
</span>
cc
</span>Larger cone = <span>(3.14 * 6^2 * 18) / 3 = </span>
<span>
<span>
<span>
678.24
</span>
</span>
</span>
cc
Difference = <span>(678.24 -452.16) = </span>
<span>
<span>
<span>
226.08
</span>
</span>
</span>
cc
I think The last one in right
y |2| 6 |10 |14
x |6 |18 |30 |42
