An even function is symmetric with respect to the y-axis. One way to identify an even function is to check the exponents of its terms, all of which must be even. For constants, we assume the exponent is zero (still considered an even number for this purpose). The first function will have an odd exponent because the expansion has a 2x term. The second function has 8x, which is also an odd exponent of 1. The third function has an odd exponent in x.
The fourth function is just a constant (with exponent 0), so it is an even function.
Answer:
4x³
Step-by-step explanation:
d/dx ln(x⁴ + 7) = 1/(x⁴ + 7) × _?
To obtain the missing expression, let us simplify d/dx ln(x⁴ + 7). This can be obtained as follow:
Let y = ln (x⁴ + 7)
Let u = (x⁴ + 7)
Therefore,
ln(x⁴ + 7) = ln u
Thus,
y = ln u
dy/du = 1/u
Next, we shall determine du/dx. This is illustrated below:
u = (x⁴ + 7)
du/dx = 4x³
Finally, we shall determine dy/dx of ln (x⁴ + 7) as follow:
dy/dx = dy/du × du/dx
dy/du = 1/u
du/dx = 4x³
dy/dx = 1/u × 4x³
But:
u = (x⁴ + 7)
Therefore,
dy/dx = 1/(x⁴ + 7) × 4x³
Thus, the missing expression is 4x³
Answer:
jh
Step-by-step explanation:
<u><em>uirhgurhehgu5rhginiurogherughre hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii</em></u>
Answer:
$580
Step-by-step explanation:
25%+45%=70%
108+66=174
174 = 30%
174/3=58
58=10%
58x10=580
100%=580
