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OleMash [197]
3 years ago
10

2t+8 > -4 (t+1) THE > HAS A LIL LINE UNDER IT :) > = ____ _

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0
2t + 8 ≥ -4(t+1)

PEMDAS

2t + 8 ≥ -4t - 4

2t + 12 ≥ -4t

12 ≥ -6t

-2 ≤ t
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The cones below are similar, although not drawn to scale
kenny6666 [7]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is the slope of the line containing the midpoint of the segment with endpoints at $(2, 4)$ and $(0, -2)$ and the midpoint o
oksian1 [2.3K]

The Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.

<h3>What is the slope of line?</h3>

The slope of a line segment is a measure of the steepness of the line segment. It is the ratio of rise (the change in vertical height between the endpoints) over run (the change in horizontal length between the endpoints.

The slope of a line is a measure of its steepness. Mathematically, slope is calculated as "rise over run" (change in y divided by change in x).

Whenever the equation of a line is written in the form y = mx + b, it is called the slope-intercept form of the equation. The m is the slope of the line.

Midpoints of 1 line segment are -

= (2+0 / 2 , 4-2 / 2)

= (1,1)

Mid points of line 2 =

= (5+1 / 2, 1+5 / 2)

= (3,3)

slope  -

The required slope = rise / run

= (y1-y2)/(x1-x2)

= (1-3)/(1-3)

= 1

Therefore, the Midpoint 1 = (1,1), Mid point 2 = (3,3 ) and slope is 1 of the given points of the line.

To learn more about slope and mind-points from the given link

brainly.com/question/5792883

#SPJ4

6 0
1 year ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
Approximately 7.5 × 10^5 gallons of water flow over a waterfall each second. There are 8.6 × 10^4 seconds in one day. Approximat
tino4ka555 [31]

Answer:

6.45 \times  {10}^{10}

6 0
2 years ago
Miss Lopez had 618 and 5400s in her checking account she deposits 50 and 2500 into her account how much will she have left in he
34kurt
618+5400=6018
6018+(50+2500)=8568
8568-(47+2900)=5621
she has $5,621 in her account
8 0
3 years ago
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