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jasenka [17]
3 years ago
14

If Juliana and Brody hiked 3 2/3 trail and 2 5/6 trail how far did they hike

Mathematics
1 answer:
amid [387]3 years ago
8 0

Part of trail hiked by Juliana = 3 \frac{2}{3}

Part of trail hiked by Brody = 2 \frac{5}{6}

We have to calculate that how part did they hike.

Total part of the trail hiked by Juliana and Brody is calculated by adding the part of trail hiked by them individually.

So, total distance traveled

= 3 \frac{2}{3} + 2 \frac{5}{6}

= \frac{11}{3} + \frac{17}{6}

LCM of 3 and 6 is 6.

= \frac{22+17}{6}

= \frac{39}{6}

= \frac{13}{2}

= 6 \frac{1}{2}

So, Juliana and Brody traveled 6 \frac{1}{2} far.

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Solve the system of linear equations.
icang [17]

Answer: The set does not have a solution

Step-by-step explanation:

Adding Equations 1 & 3 we get 5x = 7. This gives x = 7/5

Putting this value of x in eq. 2 we get

-2y + 2z = -1-(7/5) or

2y - 2z = 12/5  or  5y - 5z = 6

Multiplying eq. 1 by 2  we get  

4x + 2y - 2z = 6

adding this with eq. 2 we get 5x = 5 or x = 1

As the common solution for x from equations 1&3 does not satisfy eq. 1&2 it comes out that the three equations do not have a common solution.

Same can be verified by using different sets of two equations also.

7 0
4 years ago
Evaluate (2 - 5i)(p + q)i when p = 2 and q = 5i<br>a. 29i<br>b. 291-20<br>C.-21i<br>d.29​
attashe74 [19]

Answer:

A. 29i

Step-by-step explanation:

Step 1: Plug in given variables

(2 - 5i)(2 + 5i)i

Step 2: Difference of squares (expand)

(4 - 25i²)i

Step 3: Imaginary numbers rules

(4 - 25(-1))i

Step 4: Combine like terms

(4 + 25)i

(29)i

Your final answer will be 29i

8 0
3 years ago
Read 2 more answers
Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
maxonik [38]

Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0
3 years ago
Select the correct answer.
OLEGan [10]

Answer:

c

Step-by-step explanation:

3 0
2 years ago
The graph shows the favourite colours chosen by some middle school students. Which statement is supported by the information in
ivanzaharov [21]

Answer:

A is incorrect. 34% of the students chose red, yellow, or orange.

Step-by-step explanation:

answer will be updated when more options are given.

6 0
3 years ago
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