Question

a sprinkler that sprays water in a circular area can be adjusted to spray up to 30 feet. turning the radius-reduction screw on the top of the nozzle lets people the radius by up to 25 percent. to the nearest tenth, what is the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity.

Answer 1

Answer: 1590.4 square feet

Step-by-step explanation:

Given: The radius of the circular area = 30 feet

Now, 25% of the radius = $0.25\times30=7.5$ feet

If the we reduce the radius by 25%, then the radius of the circular area =

$30-7.5=22.5\text{ feet}$

Now, the circular area of the spray is given by :-

$\text{Area}=\pi r^2\\\\\Rightarrow\text{ Area}=(3.143.141592653)(22.5)^2\\\\\Rightarrow\text{ Area}=1590.43128088\approx1590.4\text{ ft}^2$

Therefore, the maximum area of lawn that can be watered by the sprinkler if the radius-reduction is used at full capacity = 1590.4 square feet.

Answer 2

Answer:

1590.4 square ft

Step-by-step explanation:

r=30 so you need to multiply that by 25% (30*.25=7.5)

30-7.5=22.5

A= pi(r)^2

A=pi*(22.5)^2

A=506.25pi

A=1590.43 or 1590.4 (to the nearest tenth)