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Alex777 [14]
3 years ago
12

A small 22 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0
Kinetic energy is expressed through the formula Ke=1/2mv^2, where Ke is measured in Joules (kg•m^2/s^2). For this problem, just plug in the given values:

Ke=1/2mv^2
Ke=1/2(22kg)(1m/s)^2
Ke=1/2(22)(1)
Ke=11

This canoe, with a weight of 22 kg and a speed of 1 m/s, has a kinetic energy equal to 11 Joules.
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Answer:

y = 8

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Step-by-step explanation:

Find x first. Since there is a straight line, we can conclude it's equal to 180 degrees.

11x + 10 -61 = 180

Add 10 to negative 61.

11x - 51 = 180

Add 51 to both sides.

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x = 21.

Now put x in the equations to solve.

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(21+10) = 31

This is for the big angle on the right side.

(10(21) - 61)

210 - 61 = 149.

Now for the other side, we know the degree for the smaller side on the left side since it's a vertical angle.

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3 0
3 years ago
10 十w=-9<br> I’m very confused please help
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Answer:

w = -19

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10 + w = -9

<u>-10         -10</u>

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w = -19

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While ticket prices do change (usually increase) from year to year, it's unusual to see such a situation here.

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