A small 22 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?
1 answer:
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Answer: Any real number x as long as and
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Step-by-step explanation:
You should prolly subtract 2 from both sides first.
So you get, -|2/5x + 3| > -1 2/5
- Add three to both sides
- -|2/5x| = -1 2/5
- Do -1 and 2/5 divided by 2/5 to get -3.5, x > -3.5
One of the answers is x > -3.5 but you need to switch the sign to less than and make the other side the opposite.
You see that, switched the sign and made whats on the right side opposite. So now solve for x again but with this new equation. Also, the parentheses are absolute value signs
Subtract 3 from both sides
-|2/5x| < -1 and 3/5
Divide 2/5 from each side to get x < -4
I hope I'm correct, my bad if I'm wrong
Answer:
3.9 miles
Step-by-step explanation:
Use phytagoras theorem
c²=a²+b²
4²=1²+b²
16=1+b²
b²=16-1
b²=15
b=
b= 3.872
≈3.9miles