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Alex777 [14]
3 years ago
12

A small 22 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
7 0
Kinetic energy is expressed through the formula Ke=1/2mv^2, where Ke is measured in Joules (kg•m^2/s^2). For this problem, just plug in the given values:

Ke=1/2mv^2
Ke=1/2(22kg)(1m/s)^2
Ke=1/2(22)(1)
Ke=11

This canoe, with a weight of 22 kg and a speed of 1 m/s, has a kinetic energy equal to 11 Joules.
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Kaylee has 4 1/2 yards of fabric. She wants to make an outfit that requires 6 1/3 yards of fabric. How much more fabric will she
Artyom0805 [142]

Answer:

1 5/6

Step-by-step explanation:

6 1/3-4 1/2= 19/3-9/2= 38/6-27/6= 11/6= 1 5/6

Ans: She will need 1 5/6 more fabric.

6 0
3 years ago
(17 points) <br> Determine if line AB is tangent to the circle
zlopas [31]

1. If AB is tangent to the circle, then

18^2=(2\cdot7.2)^2+10.8^2

We have

18^2=324

(2\cdot7.2)^2+10.8^2=324

so AB is indeed tangent to the circle.

2. The unlabeled leg is another radius of the circle so it has length 8. Then if AB is tangent to the circle,

(10+8)^2=8^2+15^2

but we have

(10+8)^2=324

8^2+15^2=289

so that cannot be a right triangle and AB is not tangent to the circle.

3 0
3 years ago
Sparky weighs 3/4 of her weight plus 3/4 of a pound. How much does she weigh
anyanavicka [17]
Maybe he weighs 6/8 hjjjhhhhjjjjj
4 0
3 years ago
What is x in 2x-3=15+11x
andrew-mc [135]
X = -2 is the answer
7 0
3 years ago
Find the sample space for the experiment.
Advocard [28]

Answer:

S ={(1+1=2), (1+2=3), (1+3=4), (1+4=5), (1+5=6), (1+6=7),

     (2+1=3), (2+2=4),(2+3=5),(2+4=6),(2+5=7),(2+6=8),

     (3+1=4), (3+2=5),(3+3=6),(3+4=7),(3+5=8),(3+6=9),

     (4+1=5), (4+2=6),(4+3=7),(4+4=8),(4+5=9),(4+6=10),

     (5+1=6), (5+2=7),(5+3=8),(5+4=9),(5+5=10),(5+6=11),

     (6+1=7), (6+2=8),(6+3=9),(6+4=10),(6+5=11),(6+6=12)}

Step-by-step explanation:

By definition the sample space of an experiment "is the set of all possible outcomes or results of that experiment".

For the case described here: "Toss a six-sided die twice and record the sum of the results".

Assuming that we have a six sided die with possible values {1,2,3,4,5,6}

The sampling space denoted by S and is given by:

S ={(1+1=2), (1+2=3), (1+3=4), (1+4=5), (1+5=6), (1+6=7),

     (2+1=3), (2+2=4),(2+3=5),(2+4=6),(2+5=7),(2+6=8),

     (3+1=4), (3+2=5),(3+3=6),(3+4=7),(3+5=8),(3+6=9),

     (4+1=5), (4+2=6),(4+3=7),(4+4=8),(4+5=9),(4+6=10),

     (5+1=6), (5+2=7),(5+3=8),(5+4=9),(5+5=10),(5+6=11),

     (6+1=7), (6+2=8),(6+3=9),(6+4=10),(6+5=11),(6+6=12)}

The possible values for the sum are 2,3,4,5,6,7,8,9,10,11,12

5 0
3 years ago
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