Use the factor theorem to determine which of the following is a factor of f(x)=x^3+5x2-15x+9

Mathematics

1 answer:

patriot [66]3 years ago

7 0

x+2

Step-by-step explanation:

x+2

If x = –2 is a zero, then x + 2 = 0, so x + 2 is a factor. Similarly, if x = 1/3 is a zero, then x – 1/3 = 0, so x – 1/3 is a factor. By giving me two of the zeroes, they have also given me two factors: x + 2 and x – 1/3.

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Whats the answer, can someone plz help me????

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X = 35

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Marcus is rewriting a polynomial by combining like terms. Which terms does he still need to combine to finish rewriting the poly

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Answer:-3mn^3 and -5mn^3

Step-by-step explanation:

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3 years ago

Solve.

Nikitich [7]

The answer is C: $10\text{ }^1/_2$ . Here are the details:

$\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6$

$\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3$

$\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6$

$26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6$

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3 years ago