Graph the inequality and test a point to verify your shading is correct y>3x-5
1 answer:
so, we start off by graphing its equal counterpart, its EQUALity, so we'll graph the line of y = 3x - 5.
is the line dashed or not? well y > means, "y" is greater than, not equals to, but greater than, meaning the values at the border are not included, since "y" doesn't equal them, so the line is dashed.
to do the shading, then we run a false/true test on a point on either region.....hmmmm say let's test the origin, namely 0,0,
x = 0, y = 0.
0 > 3(0) - 5
0 > -5 ................. is that true? is 0 greater than -5?, well yes, is true.
recall that on the negative side, the closer to 0, the larger the number, so -1 is greater than -1,000,000.
so the origin is in the True region, so we shade that, Check the picture below.
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Answer:
Step-by-step explanation:
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Hope this helped!
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse ²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90 °
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s) ²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4
