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VladimirAG [237]

3 years ago

9

A square piece of gold has sides that are 9 millimeters long what is the piece of golds area in square millimeters

1 answer:

cupoosta [38]3 years ago

3 0

Answer:

81 millimeters

Step-by-step explanation:

you multiply 9 times 9 for the same length sides and you get 81

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A total of 150 new recruits join an army training course. After one month, 30 have dropped out. what is the percentage decrease

Pachacha [2.7K]

So what will it be a percentage of? it will be the percentage of the original recruits, of the original 150.

for this, we need to divide the number of recruits that left over all recruits, and multiply by 100%: $\frac{30}{150} *100%= \frac{1}{5} *100%=20%$

so the number of trainees decreased by 20 %

4 0

3 years ago

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Ramona wants to buy cheese pizza for her family and friends gathering. She stop by nine wonder pizza and figures out that they h

Kryger [21]

Answer:

Large cheese

Step-by-step explanation:

The large cheese because it's two more dollars than the medium and she has a lot of people gathering

6 0

3 years ago

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Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?

Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the expression,

Distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between M(2, -3) and N(3, 1) will be,

MN = $\sqrt{(3-2)^2+(1+3)^2}$

= $\sqrt{1+16}$

= $\sqrt{17}$

Distance between M(2, -3) and O(-3, 1),

MO = $\sqrt{(2+3)^2+(-3-1)^2}$

= $\sqrt{25+16}$

= $\sqrt{41}$

Distance between N(3, 1) and O(-3, 1),

NO = $\sqrt{(3+3)^2+(1-1)^2}$

= 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

$(\sqrt{41})^2=(\sqrt{17})^2+6^2$

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0

3 years ago

A B R and P are four points on a circle with centre 0. A O R and C are four points on a different circle. The two circles inters

Slav-nsk [51]

Answer:

x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)

Step-by-step explanation:

APRB form a cyclic trapezoid

∠APO = x° (Base angle of an isosceles triangle)

∠OPR = ∠ORP (Base angle of an isosceles triangle)

∠ORB = ∠OBR (Base angle of an isosceles triangle)

∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)

Similarly;

∠ORB + ∠ORP + x° = 180°

Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR = ∠ORP we put

We also have;

∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)

Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR

Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.

6 0

3 years ago

4 times the quantity - 16 plus a number

Kisachek [45]

Answer:

4x{16+y}=?

Step-by-step explanation:

4 0

3 years ago