All categories

3 years ago

7m-8=3(2m+4)+m please help

Mathematics

1 answer:

kirill [66]3 years ago

4 0

Answer:

m=20

Step-by-step explanation:

Solve the equation:

7m - 8 = 3 ( 2 m + 4)

Multiply 3 and (2m+4)

7m - 8 = 6m + 12

Add 8 to each side

7m = 6m + 20

Subtract 6m from both sides

m = 20

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

You might be interested in

The speed of the international space station is 27,576 kilometres per hour.

Dmitriy789 [7]

(27576km/hr)(24hr/day)(orbits/42600km)=orbits/day=15.53

So the station makes 15 FULL orbits per day

(27576km/h)(1000m/km)(h/3600s)=7660m/s

7 0

3 years ago

Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.

Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

$A = {x | x^2 ≤ 5}$

To convert this into roster form, we can find solutions for x

When $x^2\leq 5\\|x|\leq \sqrt{5} =2.236$

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A= ${-2,-1,0,1,2}$

8 0

3 years ago

How would I do all of these problems

Bogdan [553]

All you have to do is figure out the bases of the figure and use the 12 and 13 in your problems and you should be able to get the right answer.

5 0

3 years ago

Please help me immediately

marshall27 [118]

Answer:

zero of a polynomial can be defined as the points where the polynomial become 0 as a whole.

An equation formed with variables, exponents and coefficient together with operation and an equal sign is called polynomial equation.

I hope this will help you

5 0

3 years ago

Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0

2 years ago