It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.
The average acceleration of the particle over this interval is given by the average rate of change of v(t),
![a_{\rm ave} = \dfrac{v(b) - v(a)}{b - a} = \boxed{\dfrac{(b^{0.7}+4b)\cos(b^2) - (a^{0.7}+4a)\cos(a^2)}{b - a}}](https://tex.z-dn.net/?f=a_%7B%5Crm%20ave%7D%20%3D%20%5Cdfrac%7Bv%28b%29%20-%20v%28a%29%7D%7Bb%20-%20a%7D%20%3D%20%5Cboxed%7B%5Cdfrac%7B%28b%5E%7B0.7%7D%2B4b%29%5Ccos%28b%5E2%29%20-%20%28a%5E%7B0.7%7D%2B4a%29%5Ccos%28a%5E2%29%7D%7Bb%20-%20a%7D%7D)
Answer:
B. (2,8), because both equations intersect at this point
The third graph represents a function.
In a function, every input (x value) has <em>exactly</em> one output (y value). If even a single input has zero or two outputs, the graph does not represent a function.
A good way of testing this is using a vertical line. As you move a vertical line from left to right across a graph, it should always be touching exactly one point on the graphed line.
In this case, every graph fails this vertical line test except for the third graph, so the third graph represents a function.
Use the substitution method for y=0
(40,0)
y=0
0=0
Answer: (40,0) It does make the equation y=0 true
The answer is C. you can check the attached picture.