Ask question

Ask question

All categories

3 years ago

14

Solve one third divided by six equals blank by rewriting it as the multiplication equation one third times one sixth equals blan

k. 18 one ninth one eighteenth six eighteenths

1 answer:

creativ13 [48]3 years ago

5 0

18 One ninth one eightinth six eighteenths answerAnswer:

it this but do it back wods

Step-by-step explanation:

You might be interested in

What’s the value of Y?

hichkok12 [17]

Answer:

7

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

raj tested his new flashlight by shinning it on his bedroom wall the beam of the light can be described by the equation x^2 y^2-

Arturiano [62]

I can get it into standard form of that certain conic section by completing the square

<span> </span> (x^2-2x)+(y^2-4y)-31=0 <span> </span> (x^2-2x+1-1)+(y^2-4y+4-4)-31=0 <span> </span> (x-1)^2-1+(y-2)^2-4-31=0 <span> </span> (x-1)^2+(y-2)^2-36=0 <span> </span> (x-1)^2+(y-2)^2=36 <span> </span> (x-1)^2+(y-2)^2=6^2

in form
(x-h)^2+(y-k)^2=r^2
r=radius
so how wide it is is the diameter which is 2 times of radius

6=radius
6 times 2=12

12 inches I assume if the units in equation is in inches

5 0

3 years ago

Read 2 more answers

What is the answer to 9*2n+3 equals -27

stealth61 [152]

Answer: n=-5/3

Step-by-step explanation:

18n=-27-3

18n=-30

N=-30/18

N=-5/3

Hope this helps! :)

5 0

3 years ago

Kareem Heats a beaker of water to a boil then he record that the water temperature decreases from 100 degrees Celsius to 19 degr

Advocard [28]

To solve for the problem, we list first all the given

Given:

Initial temperature, T1 = 100 degC
Final temperature, T2 = 19 degC
Time, t = 5 2/5 mins or 5.4 mins

Required: Change in temperature per minute

Solution:

Change in temperature per minute = (T1-T2)/t
Change in temperature per minute = (100 degC - 19 degC)/5.4 mins
Change in temperature per minute = 15 degC/min

<em>ANSWER: 15 degC per minute</em>

4 0

3 years ago

How to solve b(5px-3c)=a(qx-4) for x

dsp73

We want to determine x from the expression
b(5px - 3c) = a(qx - 4)

Expand each side.
5bpx - 3bc = aqx - 4a

Subtract aqx from each side.
5bpx - aqx - 3bc = - 4a
x(5bp - aq) - 3bc = - 4a

Add 3bc to each side.
x(5bp - aq) = 3bc - 4a

Divide each side by 5bp - aq
x = (3bc - 4a)/(5bp - aq)

Answer: $x= \frac{3bc-4a}{5bp-aq}$

8 0

3 years ago