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2 years ago

Please Help ASAP!!! Question in image below.

Mathematics

1 answer:

zaharov [31]2 years ago

8 0

I think it is the ASA theorem, but im like 70% sure.

we see two angles that are being compared in additon to the joined sides of the smaller triangle inside the larger one

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A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll

scoundrel [369]

The given equations are

12x + 4y = 152 ...........1

32x + 12y = 420 .....2

Multiplying equation 1 by 3 to make coefficient of y same we have:

36x+12y= 456

32x+12y=420

Subtracting the two equations we have:

4x=36.

Dividing by 4 both sides

x= 9.

Substituting x value in equation 1

12(9) + 4y = 152

108+4y=152

Subtracting 108 both sides: 4y=44.

Dividing both sides by 4.

y=11.

cost of the vegetarian lunch is $11.

In the equations, x represents the cost of a chicken lunch and y represents the cost of a vegetarian lunch.

5 0

2 years ago

Help please gotta finish bbb

igomit [66]

Answer:

the third one (10.75)^2

5 0

3 years ago

Read 2 more answers

Which of these rate descriptions represent unit rates? Check all that apply. 1. 100 calories for 2 servings 2. $5 for every poun

hjlf

Answer:4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

How do you round up/down numbers PLEASE ANSWER

Nookie1986 [14]

Answer:If the number is over 5 then you go to the next number

Step-by-step explananation

7.99 = 8 its over 5

6 0

2 years ago

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Using the Rational Root Theorem, what are all the rational roots of the polynomial f(x) = 20x4 + x3 + 8x2 + x – 12?

igomit [66]

Answer:

Option 1 is correct.

Step-by-step explanation:

The given polynomial is

$f(x)=20x^4+x^3+8x^2+x-12$

we have to find all the rational roots of the polynomial f(x)

The Rational Root Theorem states that the all possible roots of a polynomial are in the form of a rational number i.e in the form of $\frac{p}{q}$

where p is a factor of constant term and q is the factor of coefficient of leading term.

In the given polynomial the constant is -12 and the leading coefficient is 20.

$\text{All possible factor of -12 are }\pm1,\pm2, \pm3, \pm4,\pm6,\pm12$

$\text{All possible factor of 20 are }\pm1,\pm2,\pm4,\pm5,\pm10,\pm20$

So, the all possible rational roots of the given polynomial are,

$\pm1,\pm2, \pm3, \pm4,\pm6,\pm12,\pm\frac{1}{2},\pm\frac{3}{2},\pm\frac{1}{4},\pm\frac{3}{4},\pm\frac{1}{10},\pm\frac{1}{5},\pm\frac{3}{5},\pm\frac{3}{10},\pm\frac{2}{5},\pm\frac{6}{5},\pm\frac{1}{20},\pm\frac{3}{20},\pm\frac{4}{5},\pm\frac{12}{5}$

Now, the rational roots of polynomial satisfy the given polynomial

$f(-\frac{4}{5})=20(-\frac{4}{5})^4+(-\frac{4}{5})^3+8(-\frac{4}{5})^2-\frac{4}{5}-12=\frac{256}{625}\times 20-\frac{64}{125}+\frac{128}{125}-\frac{4}{5}-12$