Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
Answer:
He made a mistake in the second line.
Step-by-step explanation:
He factored out x out of 6-2x and 5+4x, which is not possible because there is not an x in both 6 and 5.
Quadrant IV is also known as the 4th quadrant. Imagine it like a C: 1st quadrant is in the top right, 2nd quadrant is in the top left, 3rd quadrant is in the bottom left, and the 4th quadrant is in the bottom right. With this information in mind, the answer is A) P, B, K
Answer:
4/5 ÷3/5
4/5×5/3(any time one is dividing a fraction, the dominator would go up while the numerator would come down).
=4/3
