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3 years ago

The point A(4, 2) is reflected over the point (-1,4) and it's image is point B. What

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

7 0

Answer:

B = (-6, 6)

Step-by-step explanation:

If M is the midpoint of AB, then ...

B = 2M - A

B = 2(-1, 4) -(4, 2) = (-2-4, 8-2)

B = (-6, 6)

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3 years ago

The area of the curved surface of a solid cylinder is equal to 2 by 3 of the total area of the same cylinder if the total surfac

Aleksandr-060686 [28]

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3 years ago

Answer this question for me please cause I'm so lost and I have no clue what I am doing

Airida [17]

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4 years ago

Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw

vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

$P(X \leq x) = \frac{x - a}{b-a}$

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so $a = 40, b = 65$

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

$P(X < 50) + P(X \geq 50) = 1$

The intervals can be open or closed, so

$P(X < 50) = P(X \leq 50)$

We have that

$P(X \geq 50) = 1 - P(X < 50)$

$P(X < x) = \frac{50 - 40}{65 - 40} = 0.4$

$P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6$

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is $P(X \leq 55)$

$P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6$

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

$M = \frac{a+b}{2}$

$M = \frac{40+65}{2} = 52.5$

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

$S = \sqrt{\frac{(65-40)^{2}}{12}}$

$S = 7.22$

The standard deviation is 7.22 minutes.

5 0

3 years ago

Ray bought a shirt on sale for $18.00. The original price was $24.00. What percent was the discount?

Sunny_sXe [5.5K]

Answer:

The discount would be 25%

Step-by-step explanation:

24 and 18 are both divisible by 6

24 is just 4×6

18 is just 3×6

This means that 18/24 is the same as 3/4

We calculate the discount by subtracting the percentage of the sale price from the original price.

3/4 is the same as 75% of 100% meaning the discount percentage is 100-75, which gives us 25%

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4 years ago