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3 years ago

6

A movie rental store rented 3 times as many DVDs as videos. DVDs rent for $5 a day and videos rent for $3 a day. If the total re

ntal income for a weekend was $2160, how many DVDs and videos did the store rent

2 answers:

Yuki888 [10]3 years ago

8 0

Answer:

listen i dont know the answer but you can search it up

Step-by-step explanation:

yawa3891 [41]3 years ago

7 0

27 would be the correct answer

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a dream club charges $150 for the first month of membership, and $5 less each month after that. what is the total membership for

makkiz [27]

Answer:

1 year 1470

2 years 2220

Step-by-step explanation:

Try it, it correct

8 0

3 years ago

A classroom is 20 feet long. The office is 82% longer than the classroom. How long is the office?

enyata [817]

Answer:

The length of the office is 36.4 ft

Step-by-step explanation:

The length of the classroom = 20 ft long

The length of the office = 20 ft + 82% of the classroom length

Now, 82 % of classroom length = 82 % of 20 ft

⇒ $\frac{82}{100} \times 20 = 16.4$

or, 82% of 20 ft = 16.4 ft

⇒The length of the office = 20 ft + 16.4 ft = 36.4 ft

Hence, the length of the office = 36.4 ft

4 0

3 years ago

There is a rectangle of length xcm. The perimeter of the rectangle is 25cm. The area of the rectangle is 36cm^2. Show that 2x^2-

Alexus [3.1K]

Answer:

My thought is x = 24, according to the calculations

Step-by-step explanation:

Look for a way to eliminate the squared.

6 0

3 years ago

6. A tank contains 100-gallon of pure water. At time t = 0, a solution containing 2 lb of salt per gallon flows into the tank at

SOVA2 [1]

Answer:

The answer is below

Step-by-step explanation:

Let Q represent the amount of salt in the tank at time t.

$\frac{dQ}{dt}= flow\ in - flow\ out\\ \\flow\ in=3\ gal/min*2\ lb/gal=6\ lb/min\\\\net\ gain\ in\ tank\ volume=3-4=-1, henceflow\ out= \frac{4Q}{100-t} \\\\\frac{dQ}{dt}= 6-\frac{4Q}{100-t} \\\\\frac{dQ}{dt}+ \frac{4Q}{100-t}=6\\\\The \ integrating\ factor\ is:\\\\IF=e^{\int\limits {\frac{4}{100-t} } \, dt }=e^{-4\int\limits {\frac{-1}{100-t}}=e^{-4ln(100-t)}=(100-t)^{-4}}\\\\Multiplying\ through \ by\ IF: \\\\(100-t)^{-4}\frac{dQ}{dt}+ (100-t)^{-4}\frac{4Q}{100-t}=6(100-t)^{-4}\\\\$

$Integrating:\\\\A(100-t)^{-4}=-2(100-t)^{-3}+c\\\\A=-2(100-t)+\frac{c}{(100-t)^{-4}} \\\\at, t=0,A=0\\\\0=-2(100-0)+\frac{c}{(100-0)^{-4}}\\\\c=0.02\\\\A=-2(100-t)+\frac{0.02}{(100-t)^{-4}}$

7 0

3 years ago

Factor completely 2n^2+3n-9

SVETLANKA909090 [29]

The answer is
(2n-3)(n+3)

i hope this helps :)

7 0

3 years ago