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3 years ago

Simplify (5x3− x + 14) − (3x2− 9x + 4)

Mathematics

2 answers:

34kurt3 years ago

8 0

Answer:

5x³− 3x²+ 8x + 10.

Step-by-step explanation:

Given : (5x³− x + 14) − (3x²− 9x + 4).

To find : Simplify.

Solution : We have given

(5x³− x + 14) − (3x²− 9x + 4).

On remove parenthesis

5x³− x + 14 − 3x²+ 9x - 4.

Combine like terms

5x³− 3x²+ 9x -x + 14 - 4.

5x³− 3x²+ 8x + 10.

Therefore, 5x³− 3x²+ 8x + 10.

Lisa [10]3 years ago

5 0

Simplify ( 5 x 3-x+14)-(3 x 2-9 x + 4)= 5x3 - 3x2+8x+10

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Find the square root of the following using division method . iv) 36360

sveticcg [70]

Answer:

190.684

Step-by-step explanation:

To find the square root of 36360, we place a bar over the numbers that we want to find their square root in pairs

, 1 $\dot{3}$ $\overline{63}$ $\overline{60}$

, 1 1

2, 9 2 $\overline{63}$

9 261

38, 0 2 60

0 0

380, 6 26000

, 6 22800

3806, 8 320000

, 8 304480

38068, 4 1552000

Which gives 190.684

3 63 60

We select the divisor to be the largest number which when squares will be equal to the largest number on the left which is 1

We have 1 * 1 = 1

We subtract it from the 3 to get 2

We add the 1's to get 2

We bring down the next pair which is 63 to form the next dividend, 263

We look for a number which will multiply itself to get 263, which is 9, we then have 29 × 9 = 261

We continue till we arrive at the vertical paired numbers which is 190.684.

7 0

3 years ago

How many times does X squared minus 4X -12 cross the X axis

kolbaska11 [484]

We can solve this problem using discriminant.

x^2-4x-12's discriminant is

(-4)^2-4*-12=16+48 which is clearly larger than 0

This means that it crosses over the axes 2 times.

In case you don't know what discriminant is, its in equation ax^2+bx+c

the discriminant is b^2-4ac.

If its positive it has 2 crosses with x axis, if negative then 0 crosses, if 0 then 1 cross.

Hope this helped at least a little bit :D

4 0

3 years ago

Xy - 11 = 5 show the direct variation expalin your reasoning

Vedmedyk [2.9K]

Hey there, Lets solve this one by one

Firstly, add 11 to both sides

 $xy=5+11$

Now, Simplify 5+11 to 16

 $xy=16$

Finally, divide both sides by variable y

 $x = 16 /y$

5 0

3 years ago

Which symbol creates a true sentence when x equals 2? 6 • 8 – 2x _____ 6(5 + x) < > = ?

34kurt

48－4=44,in the left
6×7=42,in the right
44＞42,so ＞ is the answer

5 0

3 years ago

Read 2 more answers

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago