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3 years ago

Subtract (7x-2) - (3x-5)

Mathematics

2 answers:

jenyasd209 [6]3 years ago

5 0

Answer:

4x - 3

Step-by-step explanation:

(7x - 2) - (3x - 5)

Open the bracket and observe the signs,

7x -2 - 3x + 5 ( when the minus outside the bracket multiplies minus in the bracket, it becomes plus)

Collect like terms

7x - 3x - 2 + 5

4x - 3

Solnce55 [7]3 years ago

3 0

Answer:

4x + 3 is the answer obtained when we subtract (7x-2) - (3x-5)

Step-by-step explanation:

Given that, (7x-2)-(3x-5)

Minuend = 7x-2

Subtrahend = 3x-5

In subtraction of algebraic terms, we place the variables together and the constants together and then perform the operation

Thus,

= (7x-2)-(3x+5) opening brackets and rewrite the equation.

= 7x-2-3x+5 bring 'x' terms together

= (7x-3x)-(2-5)

= 4x-(-3)

= 4x+3

Thus, after subtracting (7x-2)-(3x-5) we get 4x+3

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3 years ago

a volley ball player servers the ball. The ball follows a path given by the equation y=-0.01x^2+0.5x+3 where x and y are measure

dolphi86 [110]

Answer:

(a)

Distance from player should be 13.82 feet or 36.2 feet

(b)

The ball will go over the net

Step-by-step explanation:

we are given

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$y=-0.01x^2+0.5x+3$

where

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(a)

net height is 8 ft

so, we can set y=8

and then we can solve for x

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$800=-x^2+50x+300$

$-x^2+50x-500=0$

$x^2-50x+500=0$

we can use quadratic formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}$

$x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)$

$x=13.82,x=36.2$

So, distance from player should be 13.82 feet or 36.2 feet

(b)

we can plug x=30 and check whether y=8 ft

$y=-0.01(30)^2+0.5(30)+3$

$y=9ft$

we know that

height of net is 8 ft

so, the ball will go over the net

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4 years ago

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lesya692 [45]

Answer:

Neither.

Step-by-step explanation:

you are correct about the pattern, so it's not adding the same number and not multiplying by the same number. So it's neither.

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