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STALIN [3.7K]
3 years ago
5

The area of a rectangular wall of a bar is 108 square feet. Its length is 6 feet longer than twice its width. Find the length an

d width of the wall of the barn.
width = __ feet
Mathematics
1 answer:
Montano1993 [528]3 years ago
6 0

Answer:

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Area of rectangle = 108 ft²

L = 2W + 6

To find the length and width of the wall of the barn;

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Simplify 4( 3+ 7y) + 6(2 - y) if y =2
UkoKoshka [18]

Answer:

68

Step-by-step explanation:

The expression is given as:

4( 3+ 7y) + 6(2 - y)

It is known that y is equal to 2. Therefore, substitute 2 in for y.

4(3+7(2))+6(2-2)

Now, solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

Solve inside of the parentheses first.

4(3+7(2))+6(2-2)

4(3+14)+6(0)

4(17)+6(0)

Multiply

68+0

Add

68

8 0
3 years ago
Kyle made a down payment of $850 towards his car loan. He will be paying $415 every month for 24 months. How Much does the car c
iren [92.7K]
$10,810. 
415*24+850. :) glad I could help
5 0
3 years ago
Read 2 more answers
For number 6, evaluate the definite integral.
maks197457 [2]
\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{(8+2x)^2}}\cdot dx\impliedby \textit{now, let's do some substitution}\\\\
-------------------------------\\\\
u=8+2x\implies \cfrac{du}{dx}=2\implies \cfrac{du}{2}=dx\\\\
-------------------------------\\\\

\bf \displaystyle \int\limits_{0}^{28}\ \cfrac{1}{\sqrt[3]{u^2}}\cdot \cfrac{du}{2}\implies \cfrac{1}{2}\int\limits_{0}^{28}\ u^{-\frac{2}{3}}\cdot du\impliedby 
\begin{array}{llll}
\textit{now let's change the bounds}\\
\textit{by using } u(x)
\end{array}\\\\
-------------------------------\\\\
u(0)=8+2(0)\implies u(0)=8
\\\\\\
u(28)=8+2(28)\implies u(28)=64

\bf \\\\
-------------------------------\\\\
\displaystyle  \cfrac{1}{2}\int\limits_{8}^{64}\ u^{-\frac{2}{3}}\cdot du\implies \cfrac{1}{2}\cdot \cfrac{u^{\frac{1}{3}}}{\frac{1}{3}}\implies \left. \cfrac{3\sqrt[3]{u}}{2} \right]_8^{64}
\\\\\\
\left[ \cfrac{3\sqrt[3]{(2^2)^3}}{2} \right]-\left[ \cfrac{3\sqrt[3]{2^3}}{2}  \right]\implies \cfrac{12}{2}-\cfrac{6}{2}\implies 6-3\implies 3
3 0
3 years ago
35,520 divided by 96
Vlada [557]

The answer would be 370

3 0
2 years ago
Which value of x is in the solution set of -3X+8≥14? ) A. -3 B. -1 C. 0 D. 3 ​
romanna [79]

Answer:

A

Step-by-step explanation:

Solving for x:

-3x + 8 ≥ 14

-3x ≥ 6

x ≤ -2

Notice the sign gets reversed when you divide or multiply by a negative number.

The only option less than -2 is -3, A.

Here's a tip: on multiple choice questions, sometimes it's faster to try each answer instead of solving the equation.  This can save time on tests like the SAT or ACT.

Let's try it:

-3(-3) + 8 = 9 + 8 = 17

-3(-1) + 8 = 3 + 8 = 11

-3(0) + 8 = 0 + 8 = 8

-3(3) + 8 = -9 + 8 = -1

So you can see the answer is A.

7 0
3 years ago
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