Somebody please help me

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.3 and P(B) = 0.7. If

Thepotemich [5.8K]

Answer:

See below

Step-by-step explanation:

What is P(A B)?

If A and B are mutually exclusive, then

P(AB) = P(A∩B) = P(∅) = 0

What is P(A | B)?

By definition

Since

P(A∩B) = 0, then P(A | B) = 0

Is P(A | B) equal to P(A)?

No, because P(A | B) = 0 and P(A) = 0.3

Are events A and B dependent or independent?

A and B would be independent if

P(A | B) = P(A) and P(B | A) = P(B)

But both P(A |B) and P(B | A) equals 0 and P(A) = 0.3, P(B) = 0.7

Hence, <em>A and B are dependent. </em>

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

No, it is not.

As we already saw, A and B are mutually exclusive but they are not independent.

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

If A and B are not empty events which are mutually exclusive, they can never be independent.

6 0

3 years ago

Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

2 years ago

P pennies added to 22 pennies

taurus [48]

23 Pennie’s is the answer I believe

7 0

2 years ago

Which shape has a larger area: a rectangle that is 7 inches by 34 inch, or a square with side length of 212 inches?

GREYUIT [131]

Answer is square with the side of 212 inches. It's area is 212×212 which is bigger than rectangular area.

7 0

2 years ago

Read 2 more answers

Part B

Georgia [21]

Answer:140

Step-by-step explanation: It is a really big number not the most reasonable answer for the low amount of marbles their are in the jar adding 58 and 82 gives you your answer

5 0

3 years ago