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Oksana_A [137]
3 years ago
15

-3x-7(x+4) which is a term in this expression

Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0
-3x, and 7(x-4) are all terms.
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What is 9/14 + 2/7 + 1/2
goldfiish [28.3K]
9/14 stays the same

2/7 turns into 4/14

1/ into 7/14

all of them added is 20/14

simplified is 1 3/7

8 0
4 years ago
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Which angles are alternate exterior angles with angle 11?
Elena-2011 [213]

The above questions answer is 8 and 14

8 0
3 years ago
What is the first step when rewriting y = 3x2 9x – 18 in the form y = a(x – h)2 k?
stiks02 [169]
A quadratic equation has the general form of: <span>

y=ax² + bx + c

It can be converted to the vertex form in order to determine the vertex of the parabola. It has the standard form of:

y = a(x+h)² - k

This can be done by completing a square. The steps are as follows:

</span><span>y = 3x2 + 9x – 18
</span>y = 3(x2 <span>+ 3x) – 18
</span>y + 27/4= 3(x2 <span>+ 3x+ 9/4) – 18 
</span>y = 3(x2 + 3/2)^2 – 99<span>/4
</span>
Therefore, the first step is to group terms with the variable x and factoring out the coefficient of x^2.
3 0
3 years ago
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If α, β are the zeroes of the polynomials f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) =
Pavlova-9 [17]

Answer:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:

f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)

4 0
3 years ago
Consider the triangle.
leva [86]

Answer:

58.5

Step-by-step explanation:

since a triangle consists 180 degrees, 180-90-31.5 would equal 58.5

6 0
2 years ago
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