Whats the squareroot of 72 needs to be simplified

Mathematics

1 answer:

Anton [14]2 years ago

5 0

Answer: 6√2

Step-by-step explanation: The easiest way to do this problem is to factor 72 as 2 · 36, then recognize 36 as a perfect square, 6 · 6.

There's no need to factor further because the 6's pair up

so a 6 comes out of the radical leaving a 2 inside.

So our answer is 6√2.

Always be on the lookout for perfect squares!

Work is attached below.

You might be interested in

Given sinθ=- 3/5 and cscθ=-5/3 in quadrant III, find the value of other trigonometric functions using a Pythagorean Identity. Sh

Yakvenalex [24]

Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinÎ¸=-3/5 cosecÎ¸=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, ă€–ACă€—^2=ă€–ABă€—^2+ă€–BCă€—^2 ------
--(1)
Since sinÎ¸=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)

ă€–BCă€—^2=ă€–ACă€—^2-ă€–ABă€—^2

ă€–BCă€—^2=5^2-3^2

ă€–BCă€—^2=25-9

ă€–BCă€—^2=16

BC=4 units

Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosÎ¸=Base/Hypotenuse CosÎ¸=-4/5
secÎ¸=Hypotnuse/Base secÎ¸=-5/4
tanÎ¸=Perpendicular/Base tanÎ¸=3/4
cotÎ¸=Base/Perpendicular cotÎ¸=4/3

4 0

2 years ago

Simplify the expression x8 y-26/x14 y-5 X x-39 y-21.

KonstantinChe [14]

$\frac{x^8y^{-26}}{x^{14}y^{-5}}[x^{-36}y^{-21}]$

We will apply these following power rule

$x^m*x^n = x^{m+n}$
$x^m/x^n=x^{m-n}$

$[ \frac{x^8}{x^{14}}][ \frac{y^{-26}}{y^{-5}}][x^{-39}y^{-21}]$
$[x^{8-14}][y^{-26-5}][x^{-39}y^{-21}]$
$x^{-6}y^{-21}[x^{-39}y^{-21}]$
$[x^{-6-39}][y^{-21-21}]$
$x^{-45}y^{-42}$

8 0

3 years ago

Select the digit in the thousands place for 689,234

Travka [436]

Answer:

The answer is 9

Step-by-step explanation:

600,000, 50,000, 9,000, 200, 30, 4

4 0

1 year ago

What is a estimate of 7/10 times 16 uses a benchmark fraction

Annette [7]