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tensa zangetsu [6.8K]
3 years ago
6

What are solutions to the equation below x^2-3x+27=6x+7

Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0

x^2-3x+27=6x+7 \\ x^2-9x+20=0\\ x^2-5x-4x+20=0\\ x(x-5)-4(x-5)=0\\ (x-4)(x-5)=0\\ x=4 \vee x=5

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Answer:

x = 11.4

Step-by-step explanation:

14.12 = \frac{1}{2} ( 3.6x - 12.8 )

Rewrite so that the equation is entirely in decimals;

14.12 = 0.5( 3.6x - 12.8 )

Distribute;

14.12 = 1.8x - 6.4

Inverse operations;

14.12 = 1.8x - 6.4

+6.4            +6.4

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/1.8        /1.8

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This is the answer :
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Please help!
Vlada [557]

Option 3: 2^{\frac{5}{6}} is the right answer

Step-by-step explanation:

Given expression is:

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Hence,

Option 3: 2^{\frac{5}{6}} is the right answer

Keywords: Exponents, radicals

Learn more about exponents at:

  • brainly.com/question/4771355
  • brainly.com/question/4786449

#LearnwithBrainly

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Step-by-step explanation:

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