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ZanzabumX [31]
2 years ago
12

A manufacturer produces a commodity where the length of the commodity has approximately normal distribution with a mean of 6.5 i

nches and standard deviation of 0.5 inches. If a sample of 46 items are chosen at random, what is the probability the sample's mean length is greater than 6.3 inches? Round answer to four decimal places.
Mathematics
1 answer:
zavuch27 [327]2 years ago
5 0

The probablity that the sample's mean length is greate than 6.3 inches is0.8446.

Given mean of 6.5 inches,standard deviation of 0.5 inches and sample size of 46.

We have to calculate the probability that the sample's mean length is greater than 6.3 inches is 0.8446.

Probability is the likeliness of happening an event. It lies between 0 and 1.

Probability is the number of items divided by the total number of items.

We have to use z statistic in this question because the sample size is greater than 30.

μ=6.5

σ=0.5

n=46

z=X-μ/σ

where μ is mean and

σ is standard deviation.

First we have to find the p value from 6.3 to 6.5 and then we have to add 0.5 to it to find the required probability.

z=6.3-6.5/0.5

=-0.2/0.5

=-0.4

p value from z table is 0.3446

Probability that the mean length is greater than 6.3inches is 0.3446+0.5=0.8446.

Hence the probability that the mean length is greater than 6.3 inches is 0.8446.

Learn more about probability at brainly.com/question/24756209

#SPJ4

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Check the first attachment for better illustration on how the equilaterial triangle is.

Check the second attachment for better illustration on the triangle when its divided into a right angle triangle.

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