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AnnyKZ [126]
3 years ago
6

Write the prime factorization of 50.

German
2 answers:
Nata [24]3 years ago
7 0
Is this German I’m confused
Stella [2.4K]3 years ago
4 0

Answer:

2 · 5²

Explanation:

Lol why is the category for this german

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A triangle has side lengths of (10a+9)(10a+9) centimeters, (8a-3)(8a−3) centimeters, and (10b+7)(10b+7) centimeters. Which expre
aleksley [76]

Answer:s

1.1 Multiplication and Division

1. (a) 20 (b) 21 (c) 36 (d) 42 (e) 45 (f) 18

(g) 28 (h) 49 (i) 40 (j) 8 (k) 9 (l) 4

(m) 7 (n) 7 (o) 9 (p) 0 (q) 0 (r) 0

2. (a) 3 (b) 7 (c) 4 (d) 8 (e) 3 (f) 4 (g) 9

(h) 7 (i) 3 (j) 7 (k) 4 (l) 5 (m) 2 (n) 4

(o) 7 (p) 0 (q) 0 (r) 0

3. 24

4. 27

5. (a) 16 (b) 28 (c) 32

6. (a) 6 (b) 3 (c) 4

7. 8

8. (a) 35 (b) 14 (c) 42

9. (a) Daniel 70p, Joel 56p (b) Daniel has 14p more than Joel

10. (a) 80 (b) 64 (c) 40

11. £6

12. (a) 9 (b) 7, with 1 left over

13. Team A: 7, Team B: 21, Team C: 14, Team D: 14 14. (a) 7 (b) 5

1.2 Squares, Cubes, Square Roots and Cube Roots

1. (a) 25 (b) 36 (c) 1 (d) 49 (e) 6 (f) 1 (g) 7

(h) 5

2. (a) 27 (b) 64 (c) 216 (d) 1000 (e) 3 (f) 10

(g) 6 (h) 4

3. (a) 100 (b) 4 (c) 16 (d) 49 (e) 64 (f) 81

(g) 1 (h) 343 (i) 512 (j) 0 (k) 0 (l) 8

4. (a) 10 (b) 2 (c) 9 (d) 8 (e) 4 (f) 3

5. (a) 144 (b) 121 (c) 3375 (d) 2197 (e) 169 (f) 225

(g) 400 (h) 1331 (i) 11 (j) 20 (k) 13 (l) 15

(m) 15 (n) 13 (o) 12 (p) 11

6. (a) 52 (b) 5 (c) 116 (d) 25 (e) 16 (f) 72

(g) 1001 (h) 100

MEP Pupil Text 1-6 Answers

252

1.3 Index Notation

1. (a) 45

(b) 33

(c) 67

(d) 74

(e) 183

(f) 192

(g) 46 (h) 75

(i) 106

(j) 1005

2. (a) 81 (b) 625 (c) 2401 (d) 10 000 (e) 1 (f) 729

(g) 128 (h) 2 (i) 4096 (j) 4 (k) 1 (l) 25

3. (a) 211 (b) 39

(c) 313 (d) 45

(e) 54

(f) 55

(g) 42 (h) 53

(i) 32 (j) 74

(k) 172 (l) 94

(m) 45

(n) 416 (o) 36 (p) 3 1 0 = (q) 3 3 1 =

(r) 35 (s) 37

(t) 47 (u) 50

4. (a) 22 (b) 23

(c) 24 (d) 26

(e) 33

(f) 52

(g) 43

(h) 34

(i) 53

5. (a) 313 (b) 28

(c) 411 (d) 310 (e) 29

(f) 210

(g) 35 (h) 37

(i) 35 (j) 810 (k) 73

(l) 92

(m) 2 4 4 2 or (n) 23

(o) 23

6. (a) 23

(b) 103

(c) 24 (d) 33

(e) 34

(f) 104

(g) 54

(h) 43

(i) 64

(j) 20 (k) 62

(l) 50

7. (a) 26

(b) 34

(c) 66

(d) 56

(e) 28

(f) 46

(g) 38

(h) 58

(i) 36

8. (a) 28

(b) 24 (c) 310 (d) 53

(e) 105 3

( ) (f) 75 4

( )

9. (a) 36 (b) 214 (c) 512 (d) 73

(e) 74

(f) 27

(g) 3 1 0 = (h) 4 4 1 = (i) 2 2 1 =

10. (a) a5

(b) a10 (c) x9 (d) x2 (e) y3

(f) p3

(g) q3

(h) x8

(i) b3

(j) b6

(k) c3

(l) x5

(m) y2

(n) x 0 = 1 (o) x8

(p) p4 (q) x3

(r) y4

(s) x 0 = 1 (t) x x 1 = (u) x12 (v) x8

(w) x15

(x) x54

11. (a) p = 3 (b) q = 0

12. 2 4 x

MEP Pupil Text 1-6 Answers

253

1.4 Factors

1. (a) 1, 2, 7, 14 (b) 1, 3, 9, 27 (c) 1, 2, 3, 6 (d) 1, 3, 5, 15

(e) 1, 2, 3, 6, 9, 18 (f) 1, 5, 25 (g) 1, 2, 4, 5, 8, 10, 20, 40

(h) 1, 2, 4, 5, 10, 20, 25, 50, 100 (i) 1, 3, 5, 9, 15, 45

(j) 1, 2, 5, 10, 25, 50 (k) 1, 2, 3, 4, 6, 9, 12, 18, 36 (l) 1, 2, 4, 7, 14, 28

2. (a) 1 10 2 5 5 2 10 1 × ×× × ,,, (b) 1 82 44 28 1 ×× × × ,,,

(c) 1 77 1 × × , (d) 1 93 39 1 ××× , ,

(e) 1 16 2 8 4 4 8 2 16 1 × ××× × ,,,, (f) 1 22 2 11 11 2 22 1 ×× ×× ,,,

(g) 1 11 11 1 × × ,

(h) 1 24 2 12 3 8 4 6 6 4 8 3 12 2 × × ×××× × , ,,,,, , 24 1 ×

3. (a) 4 (b) 3 (c) 3 (d) 4 (e) 5 (f) 4 (g) 11

(h) 1

4. (a) 6, 10, 20, 8, 2, 24, 4 (b) 10, 20, 15, 55

5. (a) (i) 20, 22, 24, 26 (ii) 21, 24, 27 (iii) 20, 25

(b) prime numbers

6. (a) (i) 16 (ii) 18 (b) (i) 25 (ii) 27

1.5 Prime Factors

1. 2, 3, 5, 7, 13, 19, 23

2. 53, 59

3. (a) 2 5 × (b) 237 × × (c) 2 17 2 × (d) 2 37 3 × ×

(e) 2 53 × (f) 23 5 3 × × (g) 3 11 13 × × (h) 3 5 11 2 × ×

(i) 7 11 13 × ×

4. (a) 32 25 = and 56 2 7 3 = × (b) 2 8 3 (= )

5. (a) 236 × = (b) 236 × = (c) 3 5 15 × = (d) 2

(e) 2 5 10 × = (f) 5 7 35 × = (g) 2 3 24 3 × =

(h) 2 3 13 78 ×× = (i) 3 7 147 2 × =

6. (a) 45 3 5 2 = × , 99 3 11 2 = × , 135 3 5 3 = ×

(b) (i) 3 9 2 = (ii) 3 9 2 = (iii) 3 5 45 2 × = (c) 3 9 2 =

7. (a) 5 (b) 3 5 45 2 × = (c) 2 8 3 = (d) 2 5 10 × =

(e) 2 3 24 3 × = (f) 2 3 5 30 ××= (g) 2 3 108 2 3 × =

(h) 2 11 44 2 × = (i) 2 3 7 252 2 2 × ×=

MEP Pupil Text 1-6 Answers

254

1.6 Further Index Notation

1. (a) 1

16 (b) 1

8

(c) 1

6

(d) 1

7

(e) 3 (f) 8 (g) 2

(h) 3 (i) 1 (j) 1

25 (k) 8 (l) 32 (m) 2187

(n) 125 (o) 1

2

2. (a) – 4 (b) – 1 (c) – 3 (d) 1

2

(e) − 1

2

(f) 2

(g) 3 (h) – 1 (i) 1

3

(j) – 1 (k) – 2 (l) – 2

(m) – 3 (n) 1

2

(o) – 2 (p) 1

3

(q) 2

3

(r) 2

5

3. (a) 0.125 (b) 0.05 (c) 2 (d) 4 (e) 1

225 = 0 004444 . ...

(f) 0.000125 (g) 729 (h) 27 (i) 1

2

(j) 1728

(k) 62748517 (l) 1331

4. (a) 1

a

(b) a10 (c) a4 (d) 1

6 a

(e) 1

2 a

(f) 1

6 a

(g) a8

(h) a

5

2 (i) 1

3

2 a

(j) a2 (k) 1

3 a

(l) a3

(m) a

b

2

2 (n) a

b

6

12 (o) a b 12 2 (p) b

a

4

4 (q) a

b

8

12

(r) m

n

2

6 (s) a

b

3

5 (t) m

a

2

(u) c

a b

3

4 (v) x

m2

(w) z

x y

12

8 4 (x) b

a

16

3

2

5. (a) 1

9

(b) a4 (c) y = 5

2

Explanation:

pls rain list

8 0
3 years ago
lee la información referente a las funciones del lenguaje Luengo clasifica los enunciados segun corresponde Honremos la memoria
Strike441 [17]

Answer:

Read the information regarding the functions of the Luengo language classifies the statements according to our heroes' memory

Explanation:

I hoped this helped!

3 0
3 years ago
Express the given complex number (-3) in the polar form.​
Ludmilka [50]

Answer:

Given, complex number is -3.

Let r cos θ = -3 …(1)

and r sin θ = 0 …(2)

Squaring and adding (1) and (2), we get

r^2cos^2θ + r^2sin2θ = (-3)^2

Take r2 outside from L.H.S, we get

r^2(cos^2θ + sin^2θ) = 9

We know that, cos^2θ + sin^2θ = 1, then the above equation becomes,

r^2 = 9

r = 3 (Conventionally, r > 0)

Now, subsbtitute the value of r in (1) and (2)

3 cos θ = -3 and 3 sin θ = 0

cos θ = -1 and sin θ = 0

Therefore, θ = π

Hence, the polar representation is,

-3 = r cos θ + i r sin θ

3 cos π + 3 sin π = 3(cos π + i sin π)

Thus, the required polar form is 3 cos π+ 3i sin π = 3(cos π+i sin π)

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Hope It's Helpful.....:)

8 0
2 years ago
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