Will give brainliest! How many distinct triangles can be made? I think I have to first find the measure of length b and then com
pare measure a with b and h to find the answer. Please help me out on how to find measure length b
1 answer:
Check the picture below.
this is a case of the ambiguous case with an SSA, AC and CB are the sides and the angle is at A.
the ambiguous case has two triangles, the case when B is acute, CB sticks out, and the case when B is obtuse, CB sticks inside, it just so happen that those two angles for B are "supplementary" angles.
if you check the sin⁻¹ of that, we'll get the acute version of B, that's because of the constraints on the range of the inverse sine function, and we get ∡B ≈ 36.86989765°.
and of course, the other angle for B will be 180 - 36.86989765.
this is a case of the ambiguous case with an SSA, AC and CB are the sides and the angle is at A.
the ambiguous case has two triangles, the case when B is acute, CB sticks out, and the case when B is obtuse, CB sticks inside, it just so happen that those two angles for B are "supplementary" angles.
if you check the sin⁻¹ of that, we'll get the acute version of B, that's because of the constraints on the range of the inverse sine function, and we get ∡B ≈ 36.86989765°.
and of course, the other angle for B will be 180 - 36.86989765.
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Answer: ratio a:b = 3:5 p(X, 2) = p(9, 2)
<u>Step-by-step explanation:</u>
Plot points a = (12, 5) and b = (4, -3) and draw a line segment from a to b.
Notice that when y = 2, X = 9 so point p = (9, 2) <em>see graph</em>
The distance from a to p = 3√2
The distance from b to p = 5√2
So the ratio of a:b = 3√2:5√2 = 3:5 <em>when simplified</em>
<em />
<em>To find the distance, use the distance formula OR pythagorean theorem.</em>
