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Darya [45]
2 years ago
14

What graph can be used to solve the equation 2x - 1 = x + 2?

Mathematics
1 answer:
storchak [24]2 years ago
3 0

Answer:

Step-by-step explanation:

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The vertices of figure EFGH have coordinates E(1, 3), F(2, 5), G(4, 4) , and H(3, 3) . The vertices of figure E'F'G'H' have coor
ad-work [718]
The correct answer is A) a translation 2 units right and 4 units down.

Both of the reflections listed would keep the digits but change their signs and/or placement.
A translation 2 units right subtracts 2 from the x-coordinate.  A translation 4 units down subtracts 4 from the y-coordinate.  Comparing each pre-image point to its image, we can see that is what happened.
7 0
4 years ago
(x^3+x^2-9x-6)÷(x^2-9) using long division? How would I solve?
GarryVolchara [31]
The answer is (x + 1) + 3/(x^2-9)
6 0
3 years ago
2.
Komok [63]

Answer:

Part a) 22.95+0.43x \leq 25

Part b) The maximum number of candy bars that you can purchase is 4

Part c) The change would be \$0.33

Step-by-step explanation:

Part a) Write an equation representing your shopping experience and use x for the number of candy bars

Let

x -----> the number of candy bars

we know that

The inequality that represent this problem is equal to

2(3.50)+2(2.75)+10.45+0.43x \leq 25

22.95+0.43x \leq 25

Part b) Solve the equation to determine how many candy bars can you purchase?

22.95+0.43x \leq 25

Solve for x

Subtract 22.95 both sides

0.43x \leq 25-22.95

0.43x \leq 2.05

Divide by 0.43 both sides

x \leq 2.05/0.43

x \leq 4.8

The maximum number of candy bars that you can purchase is 4

Part c) How much change would you have left?

If you purchase 4 candy bars

then

22.95+0.43(4)=\$24.67

therefore

\$25-\$24.67=\$0.33

4 0
4 years ago
How to find where the equations meet.
zzz [600]
The first sentence → x - 2y = -1
the second one → 3x - 2y = -3

multiply the first one by -1
you can get → -x + 2y = 1

plus two sentences together
you can get → 2x = -2

so you are able to know that x = -1
and y = 0
3 0
3 years ago
If 3t − 7 = 5t , then 6t = how do you solve this
Alik [6]
3t-7=5t \ \ \ |\hbox{subtract 3t} \\ -7=5t-3t \\ -7=2t \ \ \ |\hbox{multiply by 3} \\ \boxed{6t=-21}}
4 0
3 years ago
Read 2 more answers
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