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gulaghasi [49]
4 years ago
11

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance tra

veled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles). The fitted regression is Time = −7.126 + .0214 Distance, based on a sample of 20 shipments. The estimated standard error of the slope is 0.0053. Find the critical value for a right-tailed test to see if the slope is positive, using α = .05.
Mathematics
1 answer:
alina1380 [7]4 years ago
5 0

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df =  18

At the level of significance ∝ = 0.05 and degree of freedom df =  18

For a right tailed test t, the critical value from the t table is :

t_{0.05, 18} = 1.734

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Determine whether the data in the table display exponential behavior. Explain why or why not.
disa [49]

Answer:

The Answer is B

Step-by-step explanation:

7 0
3 years ago
F(x) = -1/3x find the average rate of change of f from -2 to 2
Bas_tet [7]
Average rate=(change in y)/(change in x)

if f(x)=-x/3

r=( f(2)-f(-2) )/(2--2)

r=(-2/3-2/3)/(2+2)

r=(-4/3)/4

r=-4/12

r=-1/3

For a line, this is always true, since all lines have a constant velocity, the average velocity over any interval is equal to the slope.

8 0
3 years ago
If you have a cubic polynomial of the form y = ax^3 + bx^2 + cx + d and lets say it passes through the points (2,28), (-1, -5),
Anna007 [38]

Answer:

a = 3

b = 2

c = 0

d = -4

Step-by-step explanation:

Form 4 equations and solve simultaneously

28 = a(2)³ + b(2)² + c(2) + d

28 = 8a + 4b + 2c + d (1)

-5 = -a + b - c + d (2)

220 = 64a + 16b + 4c + d (3)

-20 = -8a + 4b - 2c + d (4)

(1) + (4)

28 = 8a + 4b + 2c + d

-20 = -8a + 4b - 2c + d

8 = 8b + 2d

d = 4 - 4b

Equation (2)

c = -a + b + d + 5

c = -a + b + 4 - 4b+ 5

c = -a - 3b + 9

28 = 8a + 4b + 2c + d (1)

28 = 8a + 4b + 2(-a - 3b + 9) + 4 - 4b

28 = 6a - 6b + 22

6a - 6b = 6

a - b = 1

a = b + 1

220 = 64a + 16b + 4c + d (3)

220 = 64(b + 1) + 16b + 4(-b - 1 - 3b + 9) + 4 - 4b

220 = 60b + 100

60b = 120

b = 2

a = 2 + 1

a = 3

c = -3 - 3(2) + 9

c = 0

d = 4 - 4(2)

d = -4

8 0
3 years ago
Read 2 more answers
Help please!! Step by step!!
GarryVolchara [31]

Answer:

P(Ice Cream|Frogtown) = 67.4\%

Step-by-step explanation:

Given

The attached plot

Required

P(Ice Cream|Frogtown)

This is calculated as:

P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

From the attachment;

P(Ice\ Cream\ n\ Frogtown) = 0.31

P(Frogtown) = 0.31 + 0.15 = 0.46

So, we have:

P(Ice Cream|Frogtown) = \frac{P(Ice\ Cream\ n\ Frogtown)}{P(Frogtown)}

P(Ice Cream|Frogtown) = \frac{0.31}{0.46}

P(Ice Cream|Frogtown) = 0.6739

Express as percentage

P(Ice Cream|Frogtown) = 0.6739 * 100\%

P(Ice Cream|Frogtown) = 67.39\%

P(Ice Cream|Frogtown) = 67.4\% -- approximated

5 0
3 years ago
Identify the interval(s) on which the function y = 2x^2 - 8x - 10 is positive.
Serga [27]

Given:

y=2x^2-8x-10

To find:

The interval(s) on which the given function is positive.

Solution:

We have,

y=2x^2-8x-10

y=2(x^2-4x-5)

y=2(x^2-5x+x-5)

y=2(x(x-5)+1(x-5))

y=2(x+1)(x-5)

For zeroes, y=0

2(x+1)(x-5)=0

x=-1,x=5

-1 and 5 divide the number line in three parts (-\infty , -1),(-1,5),(5,\infty ).

Interval        Selected Value      y=2(x+1)(x-5)                      Sign

(-\infty,-1)                -2                  y=2(-2+1)(-2-5)=14           +

(-1,5)                     0                   y=2(0+1)(0-5)=-10              -

(5,\infty)                       6                  y=2(6+1)(6-5)=14                 +

So, the function is positive for interval (-\infty,-1) and (5,\infty).

We can say that the function is positive for interval x < -1 and x > 5.

Therefore, the correct option is B.

8 0
3 years ago
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