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irina1246 [14]
1 year ago
10

Which of the following is equivalent to −2(4x + 8y) − 5(3q + 6p)?

Mathematics
2 answers:
Kisachek [45]1 year ago
7 0

Answer: -8x - 16y - 15q - 30p Is the correct answer

I hope this helps!

Nadusha1986 [10]1 year ago
6 0

Answer:

-8x + 16y -15q - 30p

Step-by-step explanation:

your just expanding brackets here

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Find x and y. <br>x - y = 2 <br>3x - y = 12​
omeli [17]

the answer is

X=5

y=3

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8 0
2 years ago
How do I work this out?
Crank

Answer:

$503.90

Step-by-step explanation:

6500 X .93= 6045

6045/12=503.90

8 0
3 years ago
Read 2 more answers
Help me in both please it’s a test and i need help
nataly862011 [7]

1. -2x + 3y + 5

A. -x + -x + y + y + y + 1 + 1 + 1 + 1 + 1

B. -x + -x + 2y + y + 4 + 1

D. -5x + 3x + 4y - y + 4 + 1

2. -$40 + 100 = $60 - $50 = $10

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5 0
3 years ago
A system for tracking ships indicated that a ship lies on a hyperbolic path described by 5x2 - y2 = 20. the process is repeated
zysi [14]
Answer:
The ship is located at (3,5)

Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III

Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II

To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.

Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9

We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3

Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5

Based on the above, the position of the ship is (3,5).

Hope this helps :)
8 0
3 years ago
The average temperature in Calgary, Canada, is 22 degrees celsius in July and -11 degrees celsius in January. Find the range of
dexar [7]
The range is positive 11° Celsius
3 0
3 years ago
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