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3 years ago

I am ab to ask the HARDEST question in history... you ready?

Mathematics

2 answers:

Tju [1.3M]3 years ago

6 0

Answer:

Step-by-step explanation:

0 Divided by a Number 0a=0 Dividing 0 by any number gives us a zero. Zero will never change when multiplying or dividing any number by it. Finally, probably the most important rule is: a0 is undefined You cannot divide a number by zero!

barxatty [35]3 years ago

4 0

0? I honestly had to think about this cause I’m so tired but tryna help folks lol

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Does the data below describe a linear, quadratic, or exponential function?

laiz [17]

Answer:

Linear

Step-by-step explanation:

all values for y have a constant difference of -4.

That makes it linear due to a constant difference

6 0

3 years ago

2 to the trird power plus 3 to third power - 3x4 - 5 to the seacond power divid by 5 plus (7x4)

zhenek [66]

I hope this helps ( there is no negatives )

5 0

3 years ago

The midpoint of AB is M(1, 3). If the coordinates of A are(4,1), what are the coordinates of B?

Oxana [17]

Answer:

B(-2,5)

Step-by-step explanation:

$\frac{x + 4}{2} = 1 \\ 2 \times \frac{x + 4}{2} = 1 \times 2 \\ x + 4 = 2 \\ x = 2 - 4 \\ x = - 2 \\ \frac{y + 1}{2} = 3 \\ 2 \times \frac{y + 1}{2} = 3 \times 2 \\ y + 1 = 6 \\ y = 6 - 1 \\ y = 5$

Hope that this is helpful.

Have a nice day.

6 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$