F(x) = a*x^2 + b*x + c; where a is not 0;
f(-2) = -11 => 4a -2b + c = -11;
f(4) = 13 => 16a +4b + c = 13;
f(6) = 29 => 36a + 6b + c = 29;
You must find a, b, c;
False..
if it was asking for 1/3 of the original price, it would be true
but 1/3 off....means u are paying 2/3...so u would multiply the original price by 2, then divide by 3...or u would take the original price and subtract 1/3 * the original price
I believe the answer would be d .
The ordered pair (-4, 0) is a solution to the system because it makes both equations true. -4 is your x and 0 is your y for both equations.
