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olga2289 [7]
3 years ago
10

What is 20 lbs 4 oz divided by 6?

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0

Answer:

54 oz. OR 3 3/8 lbs.

Step-by-step explanation:

1) Convert pounds to ounces. There are 16 ounces in a pound. 20 * 16 = 320.

2) Add the remaining 4 ounces. 320 + 4 = 324.

3) Divide 324 by 6. 324/6 = 54.

Final answer: 54 ounces.

NOTE: If you want the answer in pounds, divide 54 by 16. 54/16 = 3 3/8

Final answer b: 3 3/8 pounds

VLD [36.1K]3 years ago
4 0

Answer:

3.38 lb or 3lbs 6oz

Step-by-step explanation:

20 lbs x16 oz =320 oz +4 oz =324 oz

324 oz/ 6 = 54oz each

54oz = 3.38 lbs

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Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
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Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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Therefore the value of P(s₂|I) is \frac{8}{11}.

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We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

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P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

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