Answer:
y=5
Step-by-step explanation:
y= 5 is always parallel to x axis
Answer:
<h3>The volume of the prism is cubic
centimeters.</h3><h3>
Step-by-step explanation:</h3><h3>Given that a rectangular prism has the following dimensions:</h3><h3>
</h3><h3>We know that a rectangular prism of length 'l', width 'w' and height 'h' is given by</h3><h3>
</h3><h3>Therefore, the volume of the given prism will be</h3><h3>
</h3><h3>Thus, the volume of the prism is
cubic centimetres.</h3>
Answer:
D. Vertex: (3, -1); zeros: (2,0), (4,0), y-intercept: (0,8)
Step-by-step explanation:
I used the desmos graphing calculator. Just plug in your equation and it should be pretty easy to find these points
Answer:
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
Step-by-step explanation:
To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.
Vcube = a³
Vsphere = (4*pi*r³)/3
Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:
Vcube = 15³ = 3375 cubic inches
Vsphere = (4*pi*(9.5/2)³)/3 = 448.921
The volume of foam there is needed to complete the box is the subtraction between the two volumes above:
Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches
The volume of foam needed to fill the box is approximately 2926.1 cubic inches.
68% will be 1 standrd deviation either side of the mean so a reasonable estimate will be (25*0.68) / 2 = 8.5
