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maria [59]
2 years ago
14

WILL CHOOSE BRAINLIEST!!! Triangle FGH has vertices F(−2, 0), G(0, 2), and H(2, 0). A dilation, centered at the origin, is appli

ed to this triangle. The image has vertices F′(−14, 0), G′(0, 14), and H′(14, 0).
What is the scale factor of this dilation?

Enter your answer in the box.
Mathematics
2 answers:
kenny6666 [7]2 years ago
5 0

Answer:

Its 3

Step-by-step explanation:

Salsk061 [2.6K]2 years ago
3 0
I think it is 7 because it is multiplied by 7
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MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
Please help. its on zearn name the coordinates of each shape<br>​
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Answer:

circle: 2, 1/2

square: 1 1/2, 3 1/2

triangle: 0, 4 1/2

7 0
2 years ago
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Would it be 7 over 20
8 0
3 years ago
The circumference of a pizza is 56.52 in. One-fourth of the pizza has been eaten the area of the remaining pizza in sq. Inches r
BabaBlast [244]
Circumference = πD
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Answer: 190.64 in²


4 0
4 years ago
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