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nydimaria [60]
3 years ago
12

John Stone rents a car. John has a fixed rate of $49.00 weekly, pays $14.00 per week for the optional insurance, and he spends $

12.00 weekly on gas. What will his cost be per month (four weeks)?
Mathematics
2 answers:
charle [14.2K]3 years ago
4 0
300 dollars per month
jekas [21]3 years ago
4 0

Answer:

Total cost of John Stone of renting a car per month = $300

Step-by-step explanation:

Fixed rate of renting a car = $49

Total fixed rate of renting for 4 weeks = 4 × 49

                                                                 = $196

Amount paid for optional insurance per week = $14

Total amount paid for optional insurance in 4 weeks = 4 × 14

                                                                                           = $56

Amount spent on gas each week = $12

Total amount spent on gas in 4 weeks = 4 × 12

                                                                  = $48

Therefore, Total cost per month = 196 + 56 + 48

                                                       = $300

Hence, Total cost of John Stone of renting a car per month = $300

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One apple and three oranges cost $5.10 and another 5 oranges and one Apple cost $7.50 what is the price of one apple and one ora
alekssr [168]

Answer:

$2.7

Step-by-step explanation:

Let the price of one apple be x

and the price of one orange y

Hence ;

One apple and 3 oranges would cost:

x + 3×y = $5.10----------------------------(1)

One apple and 5 oranges would cost;

x + 5×y = $7.50--------------------------(2)

Subtracting eqn (1) from (2), we have :

x-x + 5y -3y = 7.5- 5.1

2y = 2.4

y = $1.2

From eqn(1)

x + 3y = $5.10

x= $5.10-3($1.2) = $5.10-$3.6 = $1.5

Hence x=$1.5 and y= $1.2

We are required to find the cost of one apple and one orange, hence :

x+y = $1.5+$1.2= $2.7

4 0
3 years ago
4 /5 fraction can be rewritten as _____
patriot [66]

Answer:

8/10, 12/15, 16/20 and so on

Step-by-step explanation:

4x2/5x2 = 8/10
4x3/5x3 = 12/15
4x4/5x4 = 16/20 and so on

3 0
2 years ago
Trapezoids and kites
lisov135 [29]

QUESTION 3

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 36\degree +70\degree+m.

\Rightarrow 106\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles of the kite are congruent.

\Rightarrow m

\Rightarrow m.

\Rightarrow 2m.

\Rightarrow m.

\Rightarrow m.

QUESTION 4

RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.

Using the Pythagoras Theorem, we obtain;

|RH|^2=12^2+20^2

|RH|^2=144+400

|RH|^2=544

|RH|=\sqrt{544}

|RH|=4\sqrt{34}

QUESTION 5

The given figure is an isosceles trapezium.

The base angles of an isosceles trapezium are equal.

Therefore m

QUESTION 6

The measure of angle Y and Z are supplementary angles.

The two angles form a pair of co-interior angles of the trapezium.

This implies that;

m

\Rightarrow m

\Rightarrow m

QUESTION 7

The sum of the interior angles of a kite is 360\degree.

\Rightarrow 48\degree +110\degree+m.

\Rightarrow 158\degree+m.

\Rightarrow m.

\Rightarrow m.

But the two remaining opposite angles are congruent.

\Rightarrow m

\Rightarrow m.

\Rightarrow 2m.

\Rightarrow m.

\Rightarrow m.

QUESTION 8

The diagonals of the kite meet at right angles.

The length of BC can also be found using Pythagoras Theorem;

|BC|^2=4^2+7^2

\Rightarrow |BC|^2=16+49

\Rightarrow |BC|^2=65

\Rightarrow |BC|=\sqrt{65}

QUESTION 9.

The sum of the interior angles of a trapezium is 360\degree.

\Rightarrow m.

\Rightarrow m.

But the measure of angle M and K are congruent.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

\Rightarrow m.

6 0
3 years ago
Given f(x) = 2(4 – x)2, what is the value of F(15)? Record your answer and fat in the bubbles on your anser document​
kari74 [83]

Answer:

f(15) = 242

Step-by-step explanation:

Step 1: Define

f(x) = 2(4 - x)²

f(15) = x = 15

Step 2: Substitute and Evaluate

f(15) = 2(4 - 15)²

f(15) = 2(-11)²

f(15) = 2(121)

f(15) = 242

6 0
3 years ago
An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand
stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis H_{0} =µ  =800

alternative hypothesis  H_{1} = µ ≠ 800

<u>Step 2</u>:-

The 't' test statistic t =  \frac{x-μ}{\frac{sig}{\sqrt{n} } }

                             t = \frac{788-800}{\frac{45}{\sqrt{30} } }

                       t = \frac{12}{8.215} = 1.4607

<u>Step 3</u>:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

<u>conclusion</u>:-

A sample of 30 bulbs are came found from average µ= 800

7 0
3 years ago
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