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2 years ago

If f(x) = 8 – 10x and g(x) = 5x + 4, what is the value of (fg)(-2)?

Mathematics

1 answer:

Shkiper50 [21]2 years ago

6 0

Answer:

Step-by-step explanation:

I'm going to assume you meant "what is the value of f(g(-2))?"

g(-2) = 5(-2) + 4 = -6

f(-6) = 8 - 10(-6) = 68

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Pls pls help me I will mark you brainest

Ann [662]

Answer:

130

Step-by-step explanation:

10+10+5+5=30

50+50=100

30+100=130

5 0

2 years ago

Match the properties with the steps to solving the following equation. (8.x – 6) = x + 9

lesantik [10]

Answer:

8x - 6 = x + 9 : Given

7x - 6 = 9 :Subtraction property of equality

7x = 15 : Addition property of equality

x = 15/7 : Division property of equality

x = 2.143

Step-by-step explanation:

Match the properties with the steps to solving the following equation.

(8x - 6) = x + 9

8x - 6 = x + 9 : Given

8x - x - 6 = x + 9 - x

7x - 6 = 9 :Subtraction property of equality

7x - 6 + 6 = 9 + 6

7x = 15 : Addition property of equality

7x/ 7 = 15/7

x = 15/7 : Division property of equality

x = 2.143

4 0

2 years ago

During halftime of a basketball game, a slingshot lunches t-shirts at the crowd. A T-shirt is launched from a height of 5 feet w

AfilCa [17]

Answer is 37 hope this helps

7 0

2 years ago

A 160-inch strip of metal 20 inches wide is to be made into a small open trough by bending up two sides on the long side, at rig

babymother [125]

Answer:

The value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

Step-by-step explanation:

The dimensions of given metal strip are

Length = 160 inch

Width = 20 inch

Let the side bend x inch from each sides to make a open box.

Dimensions of the box are

Length = 160-2x inch

Breadth = 20-2x inch

Height = x inch

The volume of a cuboid is

$V=length\times breadth \times height$

Volume of box is

$V(x)=(160-2x)\times (20-2x)\times x$

$V(x)=(160-2x)(20-2x)x$

$V(x)=4 x^3 - 360 x^2 + 3200 x$

Differentiate with respect to x.

$V'(x)=12x^2 - 720 x + 3200$

Equate V'(x)=0, to find the critical points.

$0=12x^2 - 720 x + 3200$

Using quadratic formula,

$x=30\pm 10\sqrt{\frac{\left(19\right)}{3}}$

The critical values are

$x_1=30+10\sqrt{\frac{\left(19\right)}{3}}\approx 55.166$

$x_2=30-10\sqrt{\frac{\left(19\right)}{3}}\approx 4.834$

Differentiate V'(x) with respect to x.

$V'(x)=24x - 720$

The value of double derivative at critical points are

$V'(55.166)=24(55.166) - 720=603.984$

$V'(4.834)=24(4.834) - 720=-603.984$

Since the value of double derivative at x=4.834 is negative, therefore the trough have a maximum volume at x=4.834 inches.

8 0

3 years ago

Read 2 more answers

2. the student to faculty ratio at a small college is 17:3 the total of students and faculty is 740 how many faculty members are

balu736 [363]

#2) 629 students and 111 faculty. #3) 1259 skiers and 2518 snowboarders.

Explanation:
#1) Let S be the number of students and F be the number of faculty. S/F = 17/3.
We know that S+F = 740; subtracting F from both sides, we have S=740-F. We can use this to rewrite the proportion:
(740-F)/F=17/3.

Cross multiply:
3(740-F)=17(F).

Using the distributive property, we have
3*740-3*F=17F; 2220-3F=17F.

Add 3F to both sides:
2220-3F+3F=17F+3F
2220=20F.

Divide both sides by 20:
2220/20 = 20F/20
111=F.

There are 111 faculty members. Substitute that into our equation, S=740-F: S=740-111
S=629.

#2) Let x be the number of skiers. We know that there were 1259 more snowboarders with passes than skiers; that gives us x+1259.
The ratio of skiers to snowboarders is 1/2; this gives us the proportion x/(x+1259)=1/2.

Cross multiply:
2(x)=1(x+1259)
2x=x+1259.

Subtract x from both sides
2x-x=x+1259-x
x=1259.

There were 1259 skiers. This means there were 1259+1259=2518 snowboarders.

6 0

2 years ago